1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Veronika [31]
3 years ago
8

Suppose your car is on a 5% grade, meaning that for every 100 m you travel along the road you raise or lower only 5 m in elevati

on. If your car weighs 1500 kg, what is the component of its weight parallel to the road?
Physics
2 answers:
kvv77 [185]3 years ago
8 0

Answer:

734.215N

Explanation:

First we calculate the angle that corresponds to a 5% slope using the Tan-1 function

\beta = tan-1(5%)=2.86

then we use the component that corresponds to the direction parallel to the road, additionally we must multiply by the gravity value to find the weight(g=9.81m/s^2)

Wx=M*g*sen(2.86)=1500kg*9.81*sen(2.86)=734.215N

olya-2409 [2.1K]3 years ago
4 0

Answer:

733.47 N

Explanation:

For 5% grade, the elevation of the road is

tanθ = 5/100

θ = tan⁻¹0.05 = 2.86°. Which is the angle of elevation of the road.

The component of the weight parallel to the road is thus mgsinθ = 1500 kg × 9.8 m/s²sin2.86° = 733.47 N

You might be interested in
A basketball is rolling with a velocity of 0.5 meters/second relative to the ground and due north. A tennis ball is rolling with
Lisa [10]
Since the basketball and the tennis ball both travel to the same direction relative to the ground, the velocity of the basketball relative to the tennis ball is therefore the difference of their velocities.
                                     0.5 m/s - 0.25 m/s = 0.25 m/s
Thus, the basketball travel for 0.25 m/s relative to the tennis ball. 
8 0
3 years ago
find the rate of positive acceleration of an automobile which went from a complete stop to a velocity of 30 meters per second in
maks197457 [2]

Answer:

3 m/s^2

Explanation:

acceleration= Change in velocity/time

= 30-0 / 10

= 30/10

=3 m/s^2

3 0
3 years ago
How are wave properties and energy related?<br> EXPLAIN
dexar [7]

Answer:

The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

6 0
3 years ago
types of plate boundaries where two plates separate or move apart?? does anyone know please help ??????
Shtirlitz [24]
Erosion i belive it is called
7 0
3 years ago
Read 2 more answers
A 26 foot ladder is lowered down a vertical wall at a rate of 3 feet per minute. The base of the ladder is sliding away from the
lakkis [162]

Answer:

(i) 7.2 feet per minute.

(ii) No, the rate would be different.

(iii) The rate would be always positive.

(iv) the resultant change would be constant.

(v) 0 feet per min

Explanation:

Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,

By making the diagram of this situation,

Applying Pythagoras theorem,

l^2 = x^2 + y^2-----(1)

Differentiating with respect to t ( time ),

0=2x\frac{dx}{dt} + 2y\frac{dy}{dt}  ( l = 26 feet = constant )

\implies 2y\frac{dy}{dt} = -2x\frac{dx}{dt}

\implies \frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

We have,

y = 10, \frac{dx}{dt}= -3\text{ feet per min}

\frac{dy}{dt}=\frac{3x}{10}-----(X)

(i) From equation (1),

26^2 = x^2 + 10^2

676=x^2 + 100

576 = x^2

\implies x = 24\text{ feet}

From equation (X),

\frac{dy}{dt}=\frac{3\times 24}{10}=7.2\text{ feet per min}

(ii) From equation (X),

\frac{dy}{dt}\propto x

Thus, for different value of x the value of \frac{dy}{dt} would be different.

(iii) Since, distance = Positive number,

So, the value of y will always a positive number.

Thus, from equation (X),

The rate would always be a positive.

(iv) The length of the ladder is constant, so, the resultant change would be constant.

i.e. x = increases ⇒ y = decreases

y = decreases ⇒ y = increases

(v) if ladder hit the ground x = 0,

So, from equation (X),

\frac{dy}{dt}=0\text{ feet per min}

3 0
3 years ago
Other questions:
  • In the formula vy=a t what is the value of a for an object in projectile motion
    12·1 answer
  • Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.650 µC charge and flies due west at a speed of
    8·1 answer
  • How do I find the resultant force of a skydiver falling with gravity constant of 10 newtons and his weight is 70 kg??
    5·1 answer
  • The ends of a magnet where thee forces are the strongest are called magnets
    11·1 answer
  • What is the Lorentz force law used for?
    11·2 answers
  • Select all of the answers that apply.
    15·2 answers
  • Why do electrical devices have resistance​
    14·1 answer
  • Where does the body get each of these
    5·2 answers
  • Question 5
    6·1 answer
  • A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat.
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!