The answer is zero.
A simple harmonic motion has zero total mechanical energy as it moves beyond the equilibrium point, when it achieves the maximum displacement, when it moves past the equilibrium point, and when it moves past the equilibrium point and a non-zero constant.
What is simple harmonic motion?
- Simple Harmonic Motion (SHM) is a periodic, to and fro shifting rotation about the mean position of the body. The restoring force on an oscillating body is geared toward its mean direction since it is exactly proportional to its displacement.
- The sum of the potential energy and the kinetic energy constitutes the total energy in brainly.com/question/17315536.
- The particle's total mechanical energy when performing simple harmonic motion.
- The sum of the kinetic energy of the block plus the potential energy stored in the spring, which is proportional to the square of the amplitude, makes up the total energy of the block and spring system.
To learn more about simple harmonic motion visit: brainly.com/question/25380728?
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Final angular velocity = initial angular velocity plus the product of angular acceleration and time
<span>w = wo + at </span>
<span>( 1/2 ) wo = wo + at </span>
<span>- ( 1/2 ) wo = at </span>
<span>- ( 1/2 ) ( 88 rad / s ) = a ( 4.40 s ) </span>
<span>a = -10 rad /s </span>
<span>Newton's Second Law, rotational form: Torque (force perpendicular to radius) is equal to the product of moment of inertia and angluar acceleration </span>
<span>Fr = I a </span>
<span>F ( .0700 m ) = ( .850 kg m^2 ) ( -10 rad / s ) </span>
<span>F = 120 N</span>
Answer:
Explanation:
Resistivity and resistance are proportional and depends of the length and the cross-sectional area of the wire:
furthermore, the density is the mass divided by the volume, and the volume can be written as the area multiplyed by the length:
Now you have tw equations and two variables, so you can solve for each of them.
first, solve for A in both equations and replace them:
now replace this into any of the previous equiations:
If you assume the wire has circular cross-sectional area, then the area is:
solving for d:
replacing A and simplifying:
![d=2 \sqrt[4]{\frac{m\rho}{\rho_m R \pi^2} }](https://tex.z-dn.net/?f=d%3D2%20%5Csqrt%5B4%5D%7B%5Cfrac%7Bm%5Crho%7D%7B%5Crho_m%20R%20%5Cpi%5E2%7D%20%7D)
A LEVER is one type of simple machine.
