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3 years ago

The wind blows because of____.

Physics

2 answers:

gregori [183]3 years ago

5 0

The answer is:

All of the Above

seraphim [82]3 years ago

3 0

The wind blows because of____.a. Low pressure and high pressure

b. Convection in together atmosphere.

c. Uneven hearing by the sun
*uneven 'hearing' is not a real thing. However there is an uneven 'heating' of the sun

d. All of the above

Answer:
If C is a typo, the answer is D.all of the above.

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In addition to water, what things are necessary for an aquifer to form?

Virty [35]

The answer to this question is impermeable rock. water table

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3 years ago

L 9.4.3 Test (CST): Bond. Molecular Bond,

Usimov [2.4K]

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3 years ago

A string of length L, mass per unit length \mu, and tension T is vibrating at its fundamental frequency. What effect will the fo

viva [34]

The fundamental frequency on a vibrating string is given by:

$f=\frac{1}{2L}\sqrt{\frac{T}{\mu}}$

where

L is the length of the string

T is the tension

$\mu$ is the mass per unit length of the string

Keeping this equation in mind, we can now answer the various parts of the question:

(a) The fundamental frequency will halve

In this case, the length of the string is doubled:

L' = 2L

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2(2L)}\sqrt{\frac{T}{\mu}}=\frac{1}{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{2}$

So, the fundamental frequency will halve.

(b) the fundamental frequency will decrease by a factor $\sqrt{2}$

In this case, the mass per unit length is doubled:

$\mu'=2\mu$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{T}{2 \mu}}=\frac{1}{\sqrt{2}}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\frac{f}{\sqrt{2}}$

So, the fundamental frequency will decrease by a factor $\sqrt{2}$ .

(c) the fundamental frequency will increase by a factor $\sqrt{2}$

In this case, the tension is doubled:

$T'=2T$

Substituting into the expression of the fundamental frequency, we find the new frequency:

$f'=\frac{1}{2L}\sqrt{\frac{2T}{\mu}}=\sqrt{2}(\frac{1}{2L}\sqrt{\frac{T}{\mu}})=\sqrt{2}f$

So, the fundamental frequency will increase by a factor $\sqrt{2}$ .

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3 years ago

A stagehand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N. W

Diano4ka-milaya [45]

<u>Answer:</u>

Option (a)

<u>Explanation :</u>

A stage hand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N.

Hence Force applied $\text { Fapplied }=176 \mathrm{N}$

Force on piece of scenery $\mathrm{F}_{\mathrm{g}}=490 \mathrm{N}$

$\Sigma \mathrm{F} \mathrm{y}=\mathrm{F} \mathrm{n}-\mathrm{Fg}=0$

$\mathrm{Fn}=\mathrm{Fg}$

$\mathrm{FS}_{\mathrm{max}}=\mathrm{F}_{\mathrm{applied}}$

µk = $\frac{\mathrm{Fs} \max }{\mathrm{Fn}}$

= $\frac{\text { Fapplied }}{\mathrm{Fg}}$

= $\frac{176}{490}$ =0.36

coefficient of static friction is 0.36

6 0

4 years ago

A 4.00-kg model rocket is launched, expelling 64.0 g of burned fuel from its exhaust at a speed of 675 m/s. What is the velocity

olga_2 [115]

Answer:

The velocity of the rocket is 7.8 m/s

Explanation:

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3 years ago