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Inga [223]
2 years ago
6

Which type of triangle has side measures of 6 cm, 7 cm, and 12 cm and one angle with a measure of 135°?

Mathematics
1 answer:
Fittoniya [83]2 years ago
5 0

Answer:

Hm I dont know if im right but im thinking it's a scalene, because the sides are not equal, or a obtuse triangle, because one side is more than 90 degrees. Hope this helps!

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Create the exponential equation based on the scenario below: $2000 is invested in an account at an interest rate of 1.8% compoun
yarga [219]

Answer:

P(t) = 2000 · e^((1.8 / 100) ·t)

Step-by-step explanation:

8 0
3 years ago
The lid for a circular plastic food container has a diameter of 9 cm.
Levart [38]
If the diameter is 9 cm the radius is 4.5 cm (half the diameter).  The area of a circle is given by the formula:  4πr^2, where π is the constant ratio of circumference to diameter (3.14159...).

3.14 cm x 4.5 cm = 14.13 cm^2.  Remember, the units must be squared to represent area.  14.13 is extended to the nearest hundredth.
5 0
3 years ago
7. What type of angle pair are LMS and SMN? 1.adjacent angles 2.linear pair 3.complementary angles 4.vertical angles
steposvetlana [31]

In this question we have a diagram given. ANd on the basis of that diagram, we have to find the relationship between angles LMS and SMN.

As we see in the diagram, that these angles are one after another. ANd such angles are known as adjacent angles . So these two angles are adjacent angles .

So out of the four options, the correct option is the first option .

4 0
3 years ago
Drake must practice the
dybincka [34]
I’m pretty sure you do need to subtract 30-8.
8 0
2 years ago
An open box with a square base is constructed so that it has a volume of 64in^3. The base needs to be made out of a material tha
Ivahew [28]

The volume of a box is the amount of space in the box

The dimensions that minimize the cost of the box is 4 in by 4 in  by 4 in

<h3>How to determine the dimensions that minimize the cost</h3>

The dimensions of the box are:

Width = x

Depth = y

So, the volume (V) is:

V = x^2y

The volume is given as 64 cubic inches.

So, we have:

x^2y = 64

Make y the subject

y = \frac{64}{x^2}

The surface area of the box is calculated as:

A =x^2 + 4xy

The cost is:

C = 2x^2 + 4xy --- the base is twice as expensive as the sides

Substitute y = \frac{64}{x^2}

C = 2x^2 + 4x * \frac{64}{x^2}

C =2x^2 +  \frac{256}{x}

Differentiate

C' =4x -  \frac{256}{x^2}

Set to 0

4x -  \frac{256}{x^2} = 0

Multiply through by x^2

4x^3 -  256= 0

Divide through by 4

x^3 -  64= 0

Add 64 to both sides

x^3 =  64

Take the cube roots of both sides

x = 4

Recall that:

y = \frac{64}{x^2}

So, we have:

y = \frac{64}{4^2}

y = 4

Hence, the dimensions that minimize the cost of the box is 4 in by 4 in  by 4 in

Read more about volume at:

brainly.com/question/1972490

4 0
2 years ago
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