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3 years ago

In a velocity-time graph,____ is represented by the slope, or steepness, of the graph line.

Physics

1 answer:

MariettaO [177]3 years ago

3 0

Answer:

Acceleration.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

$a = \frac{v - u}{t}$

Where,

a is acceleration measured in $ms^{-2}$

v and u is final and initial velocity respectively, measured in $ms^{-1}$

t is time measured in seconds.

Hence, in a velocity-time graph, acceleration is represented by the slope, or steepness, of the graph line.

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a tungsten and coil has a resistance of 12 ohm at 15 degree celsius is the temperature coefficient of resistance of tungsten is

Dennis_Churaev [7]

Answer:

The resistance of the tungsten coil at 80 degrees Celsius is 15.12 ohm

Explanation:

The given parameters are;

The resistance of the tungsten coil at 15 degrees Celsius = 12 ohm

The temperature coefficient of resistance of tungsten = 0.004/°C

The resistance of the tungsten coil at 80 degrees Celsius is found using the following relation;

R₂ = R₁·[1 + α·(t₂ - t₁)]

Where;

R₁ = The resistance at the initial temperature = 12 ohm

R₂ = The resistance of tungsten at the final temperature

t₁ = The initial temperature = 15 degrees Celsius

t₂ = The final temperature = 80 degrees Celsius

α = temperature coefficient of resistance of tungsten = 0.004/°C

Therefore, we have;

R₂ = 12×[1 + 0.004×(80 - 15)] = 15.12 ohm

The resistance of the tungsten coil at 80 degrees Celsius = 15.12 ohm.

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3 years ago

"Place ½ teaspoon of baking soda in each large container. If the baking soda is lumpy, first place it on a small plate and use t

photoshop1234 [79]

Answer:

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4 years ago

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sertanlavr [38]

Answer:

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Explanation:

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3 years ago

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Nezavi [6.7K]

Answer: 1.124 m

Explanation:

This situation is a good example of the projectile motion or parabolic motion, and the main equations that will be helpful in this situations are:

x-component:

$x=V_{o}cos\theta t$ (1)

Where:

$V_{o}=2.80 m/s$ is the initial speed

$\theta=39\°$ is the angle at which the venom was shot

$t$ is the time since the venom is shot until it hits the ground

y-component:

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.4 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Knowing this, let's begin:

First we have to find $t$ from (2):

$0=0.4 m+2.8 m/s sin(39\°) t+\frac{-9.8m/s^{2}t^{2}}{2}$ (3)

Rearranging (3):

$-4.9 m/s^{2} t^{2} + 1.762 m/s t + 0.4 m=0$ (4)

This is a <u>quadratic equation</u> (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula: