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neonofarm [45]
3 years ago
15

Calculate the electric field at the location of a charge if the electric force is 10 newtons and the charge on the particle is 6

coulombs.
a. 0.6 j
b. 0.6 n/c
c. 1.7 v
d. 1.7 n/c
Physics
1 answer:
kolezko [41]3 years ago
6 0

I think it may be c, 1.7 v. I work with electricity a lot.


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Which of the following is an example of acceleration? I. A car speeds up. II. A car slows down. III. A car travels in a straight
svetlana [45]
I., II., and IV. are examples of acceleration. III. isn't.
6 0
4 years ago
In mechanics, massless strings are often assumed. Why is that not a good assumption when discussing waves on strings?
Marizza181 [45]

In mechanics, massless strings are often assumed. but this is not a good assumption when discussing waves on strings because the speed of a wave on a massless string would be infinite.

<h3>How to explain the information?</h3>

It should be noted that waves simply means the dynamic disturbance of a quantity.

It should be noted that in mechanics, massless strings are often assumed. but this is not a good assumption when discussing waves on strings because the speed of a wave on a massless string would be infinite.

Learn more about waves in:

brainly.com/question/15663649

#SPJ4

6 0
1 year ago
A spherical gas-storage tank with an inside diameter of 8.0 m is being constructed to store gas under an internal pressure of 1.
Mariulka [41]

Answer:

The minimum wall thickness Tmin required for the spherical tank is 65.90mm

Explanation:

Solution

Recall that,

Tmin = The minimum wall thickness =PD/2бp

where D = diameter of 8.0 m

Internal pressure = 1.62 MPa

Then

The yield strength = 295MPa/3.0 = 98.33

thus,

PD/2бp = 1.62 * 8000/ 2 *98.33

= 12960/196.66 = 65.90

Therefore the wall thickness Tmin required for the spherical tank is 65.90mm

3 0
3 years ago
Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr
soldi70 [24.7K]
Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}

GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} }  \approx 1.42\cdot 10^{12}m

3 0
3 years ago
A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the m
Fudgin [204]

Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

114 = 4 x A

A = 114/4

A = 28.5m/s²

  • U²=2as
  • U² = 2 x 28.5 x 0.12
  • U² = 6.84
  • U = √6.84
  • U = 2.62m/s
3 0
3 years ago
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