Question

A 1.25 m long pendulum on Mars

Answer 1

Try to repost so somebody answer

Answer 2

Explanation:

$period = 2\pi \sqrt{ \frac{length}{g} }$

$3.65 \: s = 2\pi \sqrt{ \frac{(1.25 \: m)}{g} }$

Squaring both sides and solving for g, we get

g = 3.70 m/s^2

which is close to what is expected (3.71 m/s^2).