1. A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly hori
1 answer:
Answer:
The net acceleration of the SUV is 0.429 meters per square second due west.
Explanation:
Statement is incomplete. Description is presented below:
<em>A SUV along with 5 passengers has a mass of 3500 kg. It has a driving force of 2500 N directed along west on a perfectly horizontal road. The surface of the road exerts a resistance force of 500 N due east. At the same time a high wind is blowing a force of 500 N due east in the opposite direction of the car's drive force. Does the car has any acceleration? If yes, then what are the magnitude and direction of the car's acceleration?</em>
According to Newton's Laws of Motion, the SUV will accelerate if and only if net acceleration is different of zero. Let suppose as positive the direction of driving force (), measured in newtons:
(1)
Where:
- Resistance force, measured in newtons.
- Wind force, measured in newtons.
- SUV net force, measured in newtons.
If we know that ,
and
, then net force experimented by the SUV is:
The car has acceleration.
By definition of force for systems with constant mass, we calculate the acceleration of the vehicle below:
(2)
Where is the mass of the SUV, measured in kilograms.
If we know that and
, then the net acceleration of the car is:
The net acceleration of the SUV is 0.429 meters per square second due west.
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Where:N1 = number of turns on primary coilN2 = number of turns on secondary coilV1 = voltage on primary coilV2 = voltage on secondary coil
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´To develop this problem we will use the concepts related to the conservation of momentum and the application of energy conservation equations to find the velocity of the mass after the collision, like this:
Velocity of the mass just before the collision
Therefore the momentum just before collision would be
Momentum after the collision
Since the momentum is conserved we have that
The velocity of mass after the collision is given by
Therefore the change in momentum of mass 2 is
Therefore the impulse acting on m2 during the collision between the two boxes is