For this specific problem, the photons have been localized to
D<span>x = </span>0.027m
uncertainty. I am hoping that this answer has satisfied your
query about and it will be able to help you, and if you’d like, feel free to
ask another question.
The mass of a substance is given in atomic mass units and is calculated by adding the average atomic masses of all the atoms in the substance's chemical formula.
<h3>What empirical formula represents the total average atomic mass of every atom?</h3>
The Method The average atomic masses of all the atoms included in a formula's representation are added to get the mass of any molecule, formula unit, or ion. It has no bearing on the number of significant figures because the number of atoms is an exact quantity. One H2O molecule weighs 18.02 amu on average.
<h3>What connection exists between the empirical formula and the molecular formula?</h3>
You can determine the number of atoms of each element in a molecule using its molecular formula. These empirical formulations provide the most basic or reduced elemental ratio of a compound. The empirical formula and the molecular formula of a substance are same if the molecular formula can no longer be decreased.
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Answer: 80m
Explanation:
Distance of balloon to the ground is 3150m
Let the distance of Menin's pocket to the ground be x
Let the distance between Menin's pocket to the balloon be y
Hence, x=3150-y------1
Using the equation of motion,
V^2= U^s + 2gs--------2
U= initial speed is 0m/s
g is replaced with a since the acceleration is under gravity (g) and not straight line (a), hence g is taken as 10m/s
40m/s is contant since U (the coin is at rest is 0) hence V =40m/s
Slotting our values into equation 2
40^2= 0^2 + 2 * 10* (3150-y)
1600 = 0 + 63000 - 20y
1600 - 63000 = - 20y
-61400 = - 20y minus cancel out minus on both sides of the equation
61400 = 20y
Hence y = 61400/20
3070m
Hence, recall equation 1
x = 3150 - 3070
80m
I hope this solve the problem.
<span>high pressure produced by the clouds because its the most likely!!!!!!!!!!</span>
The bicycle is a distance <em>x</em> away from the wall at time <em>t</em> according to
<em>x</em> = 10 m + (4 m/s) <em>t</em> + 1/2 (12 m/s²) <em>t</em> ²
so that after <em>t</em> = 8 s, it will be
<em>x</em> = 10 m + (4 m/s) (8 s) + 1/2 (12 m/s²) (8 s)² = 426 m
away from the wall.
