Answer:
Most likely it will reach 29.4 up in the air before coming back down.
Explanation:
The force of the ball will be the same on how high it will go.
Answer:
A. 1.19 * 10^(-13) N
B. 7.12 * 10^(15) m/s²
Explanation:
Parameters given:
Speed, v = 5.05 * 10^6 m/s
Angle, A = 64°
Magnetic field strength, B = 0.160T
Mass of proton, m = 1.673 * 10^(-27) kg
Charge of proton, q = 1.6023 * 10^(-19) C
A. Magnetic force is given as:
F = q*v*B*sinA
F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64
F = 1.19 * 10^(-13) N
B. Force is generally given as:
F = m*a
Hence, we can find acceleration, a, by making it the subject of formula:
a = F/m
a = (1.19 * 10^(-13))/(1.673 * 10^-27)
a = 7.12 * 10^15 m/s²
Responder:
Explicación:
Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;
T = 2Usin theta / 2
theta = 90 grados
U = 25 m / s
T = 25sin90 / 2 (9,8)
T = 25 / 19,62
T = 1,27 segundos
Por lo tanto, los cielos usarán 1.27 segundos en el aire.
La distancia horizontal es el rango;
Rango R = U√2H / g
R = 25√2 (80) /9,8
R = 25√160 / 9,8
R = 25 * √16,326
R = 25 * 4.04
R = 101,02 m
Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m
Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water
Measuring the Volume of Solids. The volume of solids is expressed in cubic measurements, such as cubic centimeter or cubic meter.
