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Harrizon [31]
3 years ago
8

Which group of elements are shiny, opaque, and have a high melting point?

Physics
1 answer:
vlabodo [156]3 years ago
3 0
The answer is A. Metals
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Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
The weight of a body of certain mass become zero in space.why?<br>​
Nady [450]

Answer:

There is no force in space.

Explanation:

Weight is the gravitational force acting on the mass as in space there is no gravity so weight appeares as zero

3 0
3 years ago
Read 2 more answers
2. What is the accelaration of a<br> 4000 kg airplane that has a force<br> of 24,000 N?
Bond [772]

Answer:

c) 6 m/s²

Explanation:

8 0
3 years ago
Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box w
musickatia [10]
The net force on the box is:
50 + 30 - 65
= 15 Newtons
This can be used in conjunction with
F = ma
to calculate the acceleration of the box if its mass is known.
3 0
3 years ago
A 41.0 kg child swings in a swing supported by two chains, each 2.98 m long. (a) If the tension in each chain at the lowest poin
Alex777 [14]

Answer:695.5 N

Explanation:

mass of child m=41 kg

Length of chain L=2.98 m

Tension in each chain T=348 N

(a)Tension at bottom point T=348 N

At lowest Point

T+T-mg=\frac{mv^2}{L}

2T-mg=\frac{mv^2}{L}

2\times 348-41\times 9.8=\frac{41\times v^2}{2.98}

v^2=\frac{294.2\times 2.98}{41}

v=\sqrt{21.38}=4.62 m/s

(b)Force exerted by Seat will be Equal to Normal reaction

N-mg=\frac{mv^2}{L}

N=mg+\frac{mv^2}{L}

N=41\times 9.8+\frac{41\times 21.38}{2.98}

N=695.95 N

8 0
3 years ago
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