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3 years ago

9

hala paid $1,202.17 for the carpet in her living room. The room has an area of 251.5 square feet. what was her unit cost of carp

eting in dollars per square foot

2 answers:

iris [78.8K]3 years ago

7 0

Answer:

4.78

Step-by-step explanation:

1202.17/251.5 = 4.78

4.78 per unit

Elena L [17]3 years ago

6 0

Answer:

$4.78 per square foot

Step-by-step explanation:

Find the unit cost by dividing the total cost by the number of square feet:

1,202.17/251.5

= 4.78

So, the unit cost is $4.78 per square foot

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the population of woodstock, Ga is about 23,896 people,and the city encompasses 11.3 square miles. What is the population densit

aev [14]

The population density of Woodstock is 2114.7 people per square mile

Step-by-step explanation:

Population density is the number of people per square kilometer or per square mile

Given

Number of people = 23896

Area = 11.3 square miles

The population density is given by the formula:

$Population\ density=\frac{Number of People}{Area}\\=\frac{23896}{11.3}\\=2114.69=>2114.7\ people\ per\ square\ mile$

Hence,

The population density of Woodstock is 2114.7 people per square mile

Keywords: Population density, Area

Learn more about population density at:

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4 years ago

Through(3,8); parallel to f(x)= 4x-2

blondinia [14]

Parallel = same slope
f(x) = 4x + b
8 = 4(3) + b, b = -4
Equation: f(x) = 4x - 4

8 0

3 years ago

WANT to keep making easy 30pts and brainliest??!!!!

earnstyle [38]

F ,B ,J are the answers

3 0

3 years ago

Read 2 more answers

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

Annette [7]

6x-2>4x-6
2x-2>-6
2x>-4
X>_ -2

5 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago