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siniylev [52]
3 years ago
5

Jello has a density of 1.14 g/mL. A box of Jello makes 475 mL of Jello and has 13 g of sugar. Determine the % m/m of sugar in th

e Jello. (Hint: d=m/v) ​
Chemistry
1 answer:
ANEK [815]3 years ago
4 0

Answer:

2.34 %

Explanation:

Since the density of the Jello, ρ = 1.14 g/mL and ρ = m/v where m = mass of jello and v = volume of jello = 475 mL.

So, m = ρv

substituting the values of the variables into the equation, we have

m = ρv

m = 1.14 g/mL × 475 mL = 541.5 g

Since we have 13 g of sugar in the jello, the total mass present is 13 g + 541.5 g = 554.5 g

So, the percentage by mass of sugar present % m/m = mass of sugar present/total mass × 100 %

= 13 g/554.5 g × 100 %

= 0.0234 × 100 %

= 2.34 %

So, the percentage by mass of sugar present % m/m = 2.34 %

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1 year ago
A chemistry student needs of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, th
mixer [17]

Answer:

34.6 cm³

Explanation:

<em>A chemistry student needs 55.0 g of carbon tetrachloride for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of carbon tetrachloride is 1.59 g/cm³. Calculate the volume of carbon tetrachloride the student should pour out. Be sure your answer has the correct number of significant digits.</em>

Step 1: Given data

  • Mass of carbon tetrachloride (m): 55.0 g
  • Density of carbon tetrachloride (ρ): 1.59 g/cm³

Step 2: Calculate the required volume of carbon tetrachloride

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