the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Answer:
simple microscope has only one lens
:)
Hey are you from Calvert too? I got the same questions for the DBA
2.00 mol C12H22O11 x (6.02 x 10^23 molecule C12H22O11 / 1 mol C12H22O11) = 1.20 x 10^24 molecules C12H22O11
hopes this answer helps :) :D :)
