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MakcuM [25]
3 years ago
11

Which of the following statements is true about gas particles?

Chemistry
2 answers:
Lynna [10]3 years ago
4 0
<h2>Answer:</h2>

There is <u>a lot of empty space between the gas particles</u>.

<h2>Explanation:</h2>

There are three states of matter called solid, liquid, and gas. Among them gas have high expanding capability. The gaseous particles have large space between them and they lack definite shape or volume. They doesn't repel with other gaseous particle due to strong force.  

As there is huge space between the particles present in the gas, they occupy the whole space of the substance in which they are kept. The strong attracting force between the particles is seen in case of solids due to which they have definite shape and volume.

satela [25.4K]3 years ago
3 0

Answer:

There is a lot of empty space between them

Explanation:

We know that gas molecules are loosely packed,

Therefore there is a lot of intermolecular space...(Which basically means that there is a lot of space between the molecules or particles in a gas)

Happy to help.

Pls mark as Brainliest.

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Using the VSEPR theory , what would the representation mean A central atom with 2 connected atoms atom with I lone pair of Jone
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The molecule has a bent geometry

Explanation:

Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.

Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.

The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.

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The new boiling point is 101.02°C. Suppose that you add another 2.0 mol of sucrose to this solution. What do you predict the new
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3 years ago
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3 years ago
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2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
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Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

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3 years ago
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Answer:

if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.

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