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egoroff_w [7]
3 years ago
13

60° 2x + 149 degrees​

Mathematics
1 answer:
MAXImum [283]3 years ago
8 0

Answer:

x = 23

Step-by-step explanation:

60°=x+14

60+14=84=X

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What is the area of the following figure? ​
USPshnik [31]

Answer:

75 mm^2

Step-by-step explanation:

use pythageron theorem to find the area of the triangle

7^2=5^2+b^2

b=4.489mm

multiply the of b by the height (5mm) to get the area. usually for the area of a triangle you divide by two, but because there is an identical triangle on the other side, it will be doubled, so dividing it by 2 is redundant.

4.489*5 = 24.49mm^2

Make a rectangle in the middle of the shape, creating a triangle on the right, like they did on the left.  That right triangle is included in the calcualtion above. the rectangle is base *height. The base is 15 - b which was 4.489. therefore the rectanlge is

5*10.1 = 50.5mm^2

add the areas together: 50.5 +24.49 = 75 mm^2

4 0
3 years ago
What is the equivalent ratio to 16 56​
julia-pushkina [17]

Answer:

The number 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Does anyone know to do this!
Rina8888 [55]
Answer: (r + 4)(r + 8)
Alright, I would first rearrange the equation by bringing all your terms to one side by adding 12r and 32 to both sides. This will result in the rearranged equation: r^2+12r+32=0
You can then factor the equation into the two binomials: (r + 4)(r + 8).
4 + 8 equals the b term, 12, and 4 x 8 equals the c term, 32.
3 0
3 years ago
4) Slope = 1, y-intercept = 4​
8090 [49]

y=mx+b - slope intercept form

Slope = 1, y-intercept = 4​

m is also the slope

b is the y-intercept

answer;

y=x+4

6 0
3 years ago
Read 2 more answers
Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr
Arisa [49]
<h2>Answer:  A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of 80mm^{2}, according to the following formula, which works for all rectangles and parallelograms:

A_{parallelogram}=(b)(h)   (1)

Where b is the base and h is the height

The<u> area of a triangle</u> is given by the following formula:

A_{triangle}=\frac{1}{2}(b)(h)   (2)

So, for option A:

A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}    

Now, the <u>area of a trapezoid </u>is:

A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)   (3)

For option B:

A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}    

For option C:

A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}>>>>This is the correct option!

For option D:

A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}    

<h2>Therefore the correct option is C</h2>
5 0
3 years ago
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