V of w sphere =
r³
Multiply by 3 on either sides to get rid of the fraction.
3V = 4
r³
Now divide either sides by 4
to isolate r³
r³
4
and 4
cancels out
= r³
Take the cube root to isolate r.
![\sqrt[3]{ \frac{3V}{4 \pi } } = \sqrt[3]{r^3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20%3D%20%20%5Csqrt%5B3%5D%7Br%5E3%7D%20)
the cube root cancels the cube
![\sqrt[3]{ \frac{3V}{4 \pi } }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3V%7D%7B4%20%5Cpi%20%7D%20%7D%20)
= r
2c3 Because when you look at it when you look at the question if I do that and then you were at the AC is at the two and see is that the three on the number line then you would add that on and you’ll get your answer
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
