Answer: 112 dm3
Explanation:
At STP, 1 mole occupied 22.4dm3
Hence
5mole will occupy 22.4×5= 112dm3
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Explanation:
Mixture is the physical Combination Of two or Substance
Example
a mixture of sugar and water.
Compound is the chemical combination of two or more metals.
Example.
a mixture of hydrogen and water.
A mixture of hydrogen and oxygen forms water or H2O
whereas The dihydrogen monoxide parody involves calling water by an unfamiliar chemical name, most often "dihydrogen monoxide" (DHMO), and listing some of water's properties in a particularly alarming manner, such as accelerating corrosion (rust) and causing suffocation (drowning). The parody often calls for dihydrogen monoxide to be banned, regulated, or labeled as dangerous. It plays into chemophobia and demonstrates how a lack of scientific literacy and an exaggerated analysis can lead to misplaced fears. The parody has been used with other chemical names such as hydrogen hydroxide, dihydrogen oxide, hydroxic acid, hydric acid and oxidane.
Answer:
We need 7.5 mL of the 1M stock of NaCl
Explanation:
Data given:
Stock = 1M this means 1 mol/ L
A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL
Step 2: Calculate the volume of stock we need
The moles of solute will be constant
and n = M*V
M1*V1 = M2*V2
⇒ with M1 = the initial molair concentration = 1M
⇒ with V1 = the volume we need of the stock
⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L
⇒ with M2 = the concentration of the new solution = 0.15 M
1*V1 = 0.15*(50)
V1 = 7.5 mL
Since 0.0075 L of 1M solution contains 0.0075 moles
50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M
We need 7.5 mL of the 1M stock of NaCl
Answer:
The value of maximum pressure the balloon could be filled = 6.40 atmosphere.
Explanation:
When helium from the cylinder is filled inside the balloon the heat & work
transfer is zero during the process. so from the first law of thermodynamics
change in internal energy is zero.
⇒ = 0
⇒ =
⇒ = ------------- (1)
Final temperature is equal to initial temperature.
Equation (1) can be written as
⇒ = -------------(2)
Initial volume = 44 L
Final volume = 296 L
Initial pressure = 43.1 atmosphere
Final pressure = we have to calculate
Put all the values in Equation (2) we get,
⇒ × 296 = 43.1 × 44
⇒ = 6.40 atmosphere
This is the value of maximum pressure the balloon could be filled.