The molarity of the solution is calculated by dividing the number of moles of the solute, in moles, by the total volume of the solution, in liters.
The molar mass of calcium hydroxide, Ca(OH)2 is calculated below.
m = molar mass Ca + 2(molar mass O) + 2(molar mass H)
Substituting,
m = 40 g/mol + 2(16 g/mol) + 2(1 g/mol)
m = 74 g/mol
To get the number of moles Ca(OH)2 in 75.8 grams,
n = (75.8 grams)(1 / 74 g/mol) = 1.024 moles
The molarity, M, is therefore,
M = (1.024 moles Ca(OH)2) / (1.2 L)
M = 0.854 M
<em>Answer: 0.854 M</em>
Molar mass
(2 x (aluminum's mass)) + (3 x ( oxygen's mass)
Nope, its A i just took the test
<span>Two neutral hydrogen atoms share electrons in a covalent bond.
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Answer:
1) Ethane is the limiting reactant
2) mass of CO₂ produced is 733.33 g
Explanation:
C₂H₆ + 2O₂ → 2CO₂ + 3H₂ ------------------------(1)
molar ratio for equation (1) can be shown as;
1 : 2 → 2 : 3
molecular weight of moles of C₂H₆ = 30 g/mol
molecular weight of moles of O₂ = 32 g/mol
molecular weight of moles of CO₂ = 44 g/mol
mass of O₂ = 220 g
mass of C₂H₆ = 250 g
number of moles of O₂ = mass ÷ molecular weight = 220 g ÷ 32 g/mol * 2 = 13.75 moles
number of moles of C₂H₆ = mass ÷ molecular weight = 250 g ÷ 30 g/mol = 8.333 moles
1) Ethane is the limiting reactant as the 8.333 moles will finish before the 13.75 moles of the oxygen is totally consumed.
2) 1 mole of C₂H₆ will form 2 moles of CO₂
Therefore, 8.333 moles will form 16.667 moles of CO₂
mass of CO₂ formed = number of moles * molecular weight = 16.667 * 44 = 733.33 g
Answer:
a) 
b) 
d) 
d) 
Explanation:
From the question we are told that:
Moles of N2 
Atmospheric pressure 
Temperature 
Initial heat 
a)
Generally the equation for change in temperature is mathematically given by
Where
b)
Generally the equation for ideal gas is mathematically given by
For v double
Therefore
Total Work-done 
c)
Generally the equation for amount of heat added is mathematically given by
d)
Generally the equation for change in internal energy of the gas is mathematically given by
