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svlad2 [7]
3 years ago
13

Science pls help me having trouble on the third one

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
6 0
The diameters of the spheres are 72.5 meters square
neonofarm [45]3 years ago
6 0

Answer:

ijcQwertyjkllmnnbbvcxzssssdttyyjnnnvvcxyj

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If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g・°C) that can be heated from 22.5°C to
inysia [295]

Answer:

The correct answer will be "18.25 g".

Explanation:

The given values are:

Specific heat,

C = 0.45 J/g・°C

Heat involved,

q =  801 J

Temperature,

ΔT = 120.0°C-22.5°C

     = 97.5°C

As we know,

⇒  C = \frac{q}{m \Delta T}

On substituting the given values, we get

⇒  0.45=\frac{801}{m(97.5)}

⇒  m = 18.25 \ g

3 0
4 years ago
32:53
Butoxors [25]

Answer:

A solution

Explanation:

Mainly because a solution is a mixture of chemically bonded elements.

3 0
3 years ago
Questions and answers about isotopes grade 8 I need this for a PowerPoint exam projects
DanielleElmas [232]

Answer:

Question: A patient is diagnosed with a damage in the thyroid gland.

Which isotope is used to treat the patient?

Option:

A. Copper-64

B. Cobalt-60

C. Carbon-14

D. Iodine-131

Correct answer : D. Iodine-131

Question: Give the definition of isotopes.

Answer : Isotopes is the atoms of elements with the same proton number but different number of neutrons.

3 0
2 years ago
Can someone help me please. This is the last day
dusya [7]
Answer: Nucleus
Pls give me brainliest.
7 0
3 years ago
Read 2 more answers
I AMMMM GIVING 45 POINTSSSS PLSSS HELPPPPPPPP
Westkost [7]

Answer:

mNaNO3 =765g

Explanation:

First, we write the balanced chemical equation representing the chemical reaction that happened between aluminum nitrate and sodium chloride.

Balanced chemical equation:

AL(NO3)3+3NaCl ⟶ 3 NaNO3+AlCl3

According to the equation, each mole of aluminum nitrate requires three moles of sodium chloride. Thus, the required number of moles of sodium chloride is

4 Mol ⋅ 3 = 12mol

Based on the data provided in the table, there were 9 moles of sodium chloride used in the reaction, which was not enough for the entirety of aluminum nitrate to react. So, sodium chloride must have been the limiting reactant.

Therefore, we use the number of moles (n) of sodium chloride to calculate the number of moles of sodium nitrate, which has a 1:1 ratio with sodium chloride.

Number of moles sodium nitrate:

nNaNO3=nNaCl

nNaNO3 = 9 mol

We can also calculate the mass (m) of sodium nitrate that was produced by multiplying its number of moles by its molar mass (MM), 85.00g/mol.

Mass of sodium nitrate produced:

mNaNO3 = nNaNO3 ⋅ MMNaNO3

mNaNO3 = 9 mol ⋅ 85.00 g/mol

mNaNO3 =765g

8 0
3 years ago
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