EASY 100 POINTS, WILL MARK BRAINLEST, 2 QUESTIONS, SHOW YOUR WORK OR NO POINTS

Chemistry

2 answers:

disa [49]3 years ago

8 0

Answer:

Explanation:

1 c. enthalpy change = enthalphies of formation of all products - enthalphies of formation of all reactants = -526.3 kcal/mol

1 d. C3H8(g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (l) ΔH = -526.3 kcal/mol

SVETLANKA909090 [29]3 years ago

5 0

Answer:

Explanation:

1. Please provide the enthalpy info - I will work on it with the info

i) Reaction a should be modified to match the number of S in equation:

2S + 2O2 -> 2SO2 deltaH = -370kJ

ii) Reaction b should be written reversely to match the reactants of SO2:

2SO2 + O2 -> 2SO3 deltaH = 256kJ

iii) Adding the equations together:

2S + 3O2 -> 2SO3

iv) Enthalpy of the combined reaction = -370+256 = -114kJ

It is negative so the reaction is exothermic.

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Why are carcinogens a concern to people?

Anarel [89]

Answer:

They have been found to cause cancer in humans meaning any release of carcinogens will increase, not decrease, CANCER RISK.

Explanation:

Certain chemicals, including benzene, beryllium, asbestos, vinyl chloride, and arsenic are known human carcinogens, meaning “they have been found to cause cancer in humans.” A persons risk of developing cancer depends on how much, how long, how often, and when they are exposed to these chemicals.

8 0

2 years ago

How many grams would be in 4.45 x 10^23 molecules of N203

SVETLANKA909090 [29]

Answer:

56.24g

Explanation:

To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).

number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23

n = 4.45/6.02 × 10^(23 - 23)

n = 0.74 × 10^0

n = 0.74moles.

Using the formula below to find the mass of N2O3;

mole = mass ÷ molar mass

Molar mass of N2O3 = 14(2) + 16(3)

= 28 + 48

= 76g/mol

mass = mole × molar mass

Mass = 0.74 × 76

Mass = 56.24g