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Licemer1 [7]
3 years ago
10

NO3 + 12 + 103 + NO2 What is being oxidized?

Chemistry
2 answers:
cestrela7 [59]3 years ago
8 0

Answer:

NO₃⁻ is reduced; I₂ is oxidized

Explanation:

I think your equation is supposed to be

NO₃⁻ + I₂ ⟶ IO₃⁻ + NO₂

If you break the equation into two half-reactions, you get

NO₃⁻ + 2H⁺ + e⁻ ⟶ NO₂ + H₂O

I₂ + 3H₂O ⟶ IO₃⁻ + 6H⁺ + 5e⁻

We see that NO₃⁻ gains an electron, so it is reduced.

I₂ loses five electrons, so it is oxidized.

erik [133]3 years ago
6 0

Explanation:

perhaps is NO3

this question is somehow not correct

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3 years ago
3. In the formation of acid rain, sulfur dioxide reacts with oxygen and water in the air to form sulfuric acid. Write a balanced
Andreyy89

Answer:

SO₂ + 0.5 O₂ + H₂O → H₂SO₄

3.83 g

Explanation:

In the formation of acid rain, sulfur dioxide reacts with oxygen and water in the air to form sulfuric acid. The balanced chemical equation is:

SO₂ + 0.5 O₂ + H₂O → H₂SO₄

The molar mass of SO₂ is 64.07 g/mol. The moles of SO₂ corresponding to 2.50 g are:

2.50 g × (1 mol/64.07 g) = 0.0390 mol

The molar ratio of SO₂ to H₂SO₄ is 1:1. The moles of H₂SO₄ formed are 0.0390 moles.

The molar mass of H₂SO₄ is 98.08 g/mol. The mass of H₂SO₄ is:

0.0390 mol × 98.08 g/mol = 3.83 g

4 0
3 years ago
Ethene is the first member of the
DanielleElmas [232]
It will be:

b. Alkyne* series

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5 0
3 years ago
Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
sergeinik [125]

Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

Formula Used:

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density

Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
3 years ago
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