Answer:
D. all options are correct
Explanation:
- There is a trade-off between the size of gametes and the number of gametes.
- The larger the gamete, the less mobile it is
- The probability that a zygote survives increases with its size, and the size of the zygote is a function of the sizes of the fusing gametes
There is a 50% probability that the flowers of a plant with pink flowers parents will have pink flowers due to incomplete dominance.
The genotypes and phenotypes that we will employ to address this issue are as follows:
RR - Red
RW - Pink
WW - White
They would have the RW genotype as the first parent plant is pink. They would have the WW genotype because the other parent is white. When the Pink flower parents are crossed, the children that might be expected from this cross
RW x RW
The progeny will be : 1 RR (Red), 2 RW (Pink) and 1 WW (White)
This shows that there is a 50% probability that the progeny will have the RW genotype and thus the pink phenotype. Additionally, we can observe that there is a 25% likelihood that the progeny will have the WW and RR genotype and the white and Red phenotype.
Learn more about the Incomplete dominance with the help of the given link:
brainly.com/question/14053639
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Answer:
mitosis
Explanation:
Gametes are produced by mitosis (not meiosis) and after fertilization a diploid zygote is created. The single zygote cell never grows or divides my mitosis. It can only divide by meiosis to produce haploid cells once more, which then produce the main adult body.
Answer:
Meiosis involves two cell divisions
Explanation:
Mitosis and meiosis are two kinds of cell divisions and one of the main differences between the two is that meiosis goes through <u>2 nuclear divisions</u>.
Meiosis has Meiosis I and Meiosis II division. In Meiosis I, the number of chromosomes in the daughter cells are only half of the parent cells. This is why it is called a reduction division, because the chromosomes will be reduced by half. In Meiosis II, the daughter cells will have the same number of chromosomes as the parent cells, which in this case is the daughter cells of meiosis I.
Answer:
Sulfolobus quinone is used to shuttle electrons from a membrane-bound hydrogenase to the sulfur reductase.
Explanation:
