Answer:
192,000 grams
Step-by-step explanation:
turn 1,344 kilograms to grams, which gives u 1344000 grams
divide 1344000 by 7 and you get 192,000 grams. Hope this helped :)
Use PEMDAS:-
3 - 3 × 6 + 2 = ?
3 - 18 + 2 = ?
-15 + 2 =
-13
3 - 3 × 6 + 2 = -13.
Answer:
y = 0.2
Step-by-step explanation:
Simplifying
-6y + 5 = 29y + -2
Reorder the terms:
5 + -6y = 29y + -2
Reorder the terms:
5 + -6y = -2 + 29y
Solving
5 + -6y = -2 + 29y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-29y' to each side of the equation.
5 + -6y + -29y = -2 + 29y + -29y
Combine like terms: -6y + -29y = -35y
5 + -35y = -2 + 29y + -29y
Combine like terms: 29y + -29y = 0
5 + -35y = -2 + 0
5 + -35y = -2
Add '-5' to each side of the equation.
5 + -5 + -35y = -2 + -5
Combine like terms: 5 + -5 = 0
0 + -35y = -2 + -5
-35y = -2 + -5
Combine like terms: -2 + -5 = -7
-35y = -7
Divide each side by '-35'.
y = 0.2
Simplifying
y = 0.2
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
The standard form of a line:
We have the equation of a line in the slope-point form:
use distributive property
add 3 to both sides
multiply both sides by 2
subtract x from both sides
change the signs
