Answer:
D.
Step-by-step explanation:
The length of the unmarked side of the triangle is found by using Pythagoras:
x sqrt (10^2 - 6^2)
= sqrt 64
= 8.
The length of the curved part = 1/2 * pi * 10 = 5pi
Perimeter = 8 + 6 + 5pi
= 14 + 5pi
<h2>
Greetings!</h2>
Answer:
B)
Step-by-step explanation:
Y intercept:
Simply substitute all the x values with 0:
When x = 0:
3(0) - 2y = 18
Move the - 2y over to the other side making it a +2y:
0 = 18 + 2y
Move the +18 over to the other side making it a -18:
-18 = 2y
Divide both sides by 2:
-9 = y
So y intercept is:
<h3> (0 , -9)</h3>
X - intercept:
Simply substitute all the Y's with 0:
3x - 3(0) = 18
3x = 18
Divide both sides by 3:
x = 6
So the X intercept is:
<h3>(6 , 0)</h3>
This means that your guess of B is correct.
<h2>Hope this helps! </h2>
Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
Answer:
3(x-2)(x+5)
Step-by-step explanation:
1. Factor out common term 3
3(x^2 +3x-10)
2. Factor (x^2 +3x-10)
3(x-2)(x+5)
Answer:
( - x, - y )
Step-by-step explanation:
The starting is always Quadrant I.
270 degrees clockwise from Quadrant I is Quadrant III.
In Quadrant III, the points will be in the form ( - x, - y ).
