Answer:
see explanation
Step-by-step explanation:
Using the cofunction identity
sec(90 - x)° = cscx° , then
7A = 90 - 5A ( add 5A to both sides )
12A = 90° ( divide both sides by 12 )
A = 7.5°
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours. Option A
<h3>Equation</h3>
c(h) = 250 + 200h
s(h) = 300 + 180h
Where,
- number of credit hours taken = h
To have equal tuition in both schools,
equate both function
250 + 200h = 300 + 180h
200h - 180h = 300 - 250
20h = 50
h = 50/20
h = 2.5 hours.
The number of credit hours a student have to take for the two tuition costs to be equal is 2.5 hours.
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Answer: DNE
Step-by-step explanation:
The distance between the two points will be given by:
d=√[(x-x1)^2+(y-y1)^2]
point z1=(3-2i) has the coordinates of (3,-2)
point z2=(5-8i) has the coordinates of (5,-8)
thus the distance between them will be:
d=√[(-8-(-2)²+(5-3)²)]
d=√[(-6)²+2²]
d=√(36+4)
d=√40
d=2√10
You have to set them all equal to 0 and then factor it out.
