Answer:
Remember the property:
a^-1 = (1/a)^1
and:
(a/b)^n = (a^n)/(b^n)
A table for a function like:
![\left[\begin{array}{ccc}x&f(x)\\&\\&\\&\\&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26f%28x%29%5C%5C%26%5C%5C%26%5C%5C%26%5C%5C%26%5Cend%7Barray%7D%5Cright%5D)
Is just completed as:
![\left[\begin{array}{ccc}x&f(x)\\x_1&f(x_1)\\x_2&f(x_2)\\x_3&f(x_3)\\x_4&f(x_4)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26f%28x%29%5C%5Cx_1%26f%28x_1%29%5C%5Cx_2%26f%28x_2%29%5C%5Cx_3%26f%28x_3%29%5C%5Cx_4%26f%28x_4%29%5Cend%7Barray%7D%5Cright%5D)
So, here we have:
y = f(x) = (1/6)^x
To complete the table, we need to find:
f(-1)
and
f(2)
So let's find these two values:
f(-1) = (1/6)^-1 = (6/1)^1 = 6
and the other value is:
f(2) = (1/6)^2 = 1/36
Then the complete table is:
![\left[\begin{array}{ccc}x&f(x)\\-2&36\\-1&6\\0&1\\1&1/6\\2&1/36\\1&1/216\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26f%28x%29%5C%5C-2%2636%5C%5C-1%266%5C%5C0%261%5C%5C1%261%2F6%5C%5C2%261%2F36%5C%5C1%261%2F216%5Cend%7Barray%7D%5Cright%5D)
those are the vertex form of a parabola... so hmmm
the vertex of this one is at 0,1 and intercepts or "solutions" are at -1 and 1, so is opening downwards, notice the picture below
that means, the squared variable is the "x", thus the form is
now, we know the vertex is at 0,1, and two x-intercepts of
thus
solve for "a", to see what that coefficient is, then plug it back in the vertex form equation
No, it has more than one. A rectangle is symmetric with respect to its diagonals, and the lines connecting the midpoints of two opposite sides.
Your answer is B!
-3.8 !
I just did this one!
Answer:
Your answer is A.
Step-by-step explanation:
5 x 12 = 60
5 x 6 = 30 / 2 = 15
60 + 15 = 75
