C. x³-4x²-16x+24.
In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.
Multiply the polynomials (x-6)(x²+2x-4)
Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:
(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)
x³+2x²-4x -6x²-12x+24
Ordering the similar monomials:
x³+(2x²-6x²)+(-4x - 12x)+24
Getting as result:
x³-4x²-16x+24
Answer:
(1, 3)
Step-by-step explanation:
The first endpoint (the one on the left) is (-3, 2). The second endpoint (the one on the right) is (5, 4). To find the midpoint, find the middle of both x and y. To do that, add the values of x and y respectively and divide by 2:
for x-value of midpoint:
(x-value of first endpoint + x-value of second endpoint) / 2
= (-3 + 5) / 2
= 2 / 2
= 1
for y-value of midpoint
(y-value of first endpoint + y-value of second endpoint) / 2
= (2 + 4) / 2
= 6 / 2
= 3
Correct answer:
15
Explanation:
This problem can be solved by applying the area formula:
Since this question provides the area of the kite and length of one diagonal, plug that information into the equation to solve for the missing diagonal.
Thus the solution is:
60=8×diagonalB2
60×2=8×diagonalB
120=8(diagonalB)
diagonalB=1208=15
Answer:
5 more of the sum would be + 5 to the final answer you are adding
Step-by-step explanation:
Answer:
B. 20.8
Step-by-step explanation:
Just got it right on edge 2021
