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Strike441 [17]
3 years ago
7

Find the value of x and the value of y.

Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

C.

Step-by-step explanation:

x is bisecting the baseline (cutting it in 2 halves of 6).

the third angle in the main overall triangle is 60 degrees.

remember, all angles in a triangle always add up to 180 degrees.

so, 180 - 60 - 60 = 60.

that means that all 3 angles are of equal size (60). and that means that all 3 sides must have the same length.

=> y = 12

and now using Pythagoras to calculate the height (x) of the triangle :

y² = x² + 6² (remember, this side is only half the baseline)

12² = x² + 6²

144 = x² + 36

x² = 108

x = sqrt(108) = sqrt(36×3) = 6×sqrt(3)

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( x + 3 ) + ( − 7 x − 1 )
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-6x +2

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( x + 3 ) + ( − 7 x − 1 )

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The radius of a circle is 3 yards. What is the circle's area?<br> r=3 yd<br> )) Use 3.14 for a.
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3 years ago
Evaluate the expressiin when a=6, b=3, and c=2: c(b+a)-a= please help
Setler [38]

Answer:

\huge{ \fbox{ \tt{12}}}

Step-by-step explanation:

\underline{ \sf{Given}} : \sf a=6, \:  b=3 \:  and  \: c=2

\underline{ \sf{To \: find }}  :   \sf{Value \: of \: the \: given \: expression}

\underline{ \underline{ \mathfrak{Let's \: solve}}} :

\bigstar{ \tt{ \: c \: ( \: b \:  +  \: a \: ) -  \: a}}

\text{Step \: 1 \: } : Plug the values of a , b and c

\mapsto{ \tt{ \: 2 \: ( \: 3 \:  +  \: 6 \: ) \:  -  \: 6}}

\text{Step \: 2} : \sf{ \: Add \: the \: numbers : 6 \: and \: 3}

\mapsto{ \sf{ \: 2 \: * \: 9 \:  -  \: 6 \: }}

\text{Step \: 3 \: } : \sf{ \: Multiply \: the \: numbers : 9 \: and \: 2}

\mapsto{ \sf{18 - 6}}

\text{Step \: 4 \:} :  \sf{Subtract \: 6 \: from \: 18}

\mapsto{ \sf{ \: 12}}

Note : Just follow the PEMDAS rule ( See attached picture )

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

8 0
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