Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15
so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields
thus

solve for "x"
what's "y"? well, y = 100 - x
The new perimeter would be 60. because the width and the height are doubled.
Answer:
2/3
Step-by-step explanation:
I am not sure
Answer:
The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Past studies suggest this proportion will be about 0.15
This means that 
Find the sample size needed if the margin of error of the confidence interval is to be about 0.04
This is n when M = 0.04. So






Rounding up
The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.