Let's replace the first, second, third, and home with letters.
first base = F
second base = S
Third base = T
home base = H
We have two triangles, ΔHTS and ΔHFS
We know HS = HS because it's a shared side.
We know FS = TS
We know that ∠HST and ∠HSF are equal.
Because of SAS, the two triangles are congruent.

According to CPCTC, TH must be congruent to FH.
Thus, the distance from home plate to third base and the distance from home plate to first base must be the same.

Have an awesome day! :)

7 0

4 years ago

Use the ratio of boys and girls and the class size to find the number of boys and number of girls in each class

3241004551 [841]

10 because 3+5=8 and 80 divided by 8 equals 10.

6 0

3 years ago

Read 2 more answers

Pls help if good at math

bearhunter [10]

Answer:

Step-by-step explanation:

All odd prime numbers up to 16:

3, 5, 7, 11, 13

All multiples of four up to 16:

4, 8, 12, 16

All of those in a list:

3, 4, 5, 7, 8, 11, 12, 13, 16

There are 9 things on that list. The probability is equal to:

$\frac{9}{16}=c) 0.563$

Please mark brainliest. Have a nice day!

8 0

3 years ago

[Calculus] find average velocity given position of particle. Show steps, please!

Simora [160]

Answer:

Step-by-step explanation:

Since we are given the position function, the average velocity will simply be the average slope of the position function.

We want to find the average velocity for time 0≤t≤3.

So, our endpoints are t = 0 and t = 3.

By substitution, the position of the particle at those times are:

$x(0)=-5(0)^2=0\text{ and } \\\\ x(3)=-5(3)^2=-45$

So, we have the two points (0, 0) and (3, -45).

Then by the slope formula, we acquire that:

$\displaystyle m=\frac{(-45)-(0)}{(3)-0}=\frac{-45}{3}=-15$

So, the average velocity of the particle is about -15.

This implies that the particle was mainly moving backwards for time 0≤t≤3.

Hence, our final answer is C.

*If you differentiated first and then did the steps above, then you found the average acceleration of the particle (in this case it stays constant), not the average velocity. Remember that the slope of the position graph is velocity, and the slope of the velocity graph is acceleration!

6 0

3 years ago