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3 years ago

Please help! 45 points !!

Mathematics

2 answers:

NeTakaya3 years ago

8 0

Answer:

A. 8.2 x 10^6

Step-by-step explanation:

To get what 4.1x10^3 is equal to you move the decimal point to the right three times. This leaves you with 4,100. To get what 2.0x10^3 is equal to, you move the decimal point to the right three times. This leaves you with 2,000. 4,100 x 2,000 is 8,200,000. Then move the decimal to the left until it is behind the 8. In order to do this, you would have to move the decimal point 6 times. So the final answer is 8.2 x 10^6.

PLEASE MARK BRAINLIEST

Anna71 [15]3 years ago

8 0

I think it’s A. 8.2 *10^6

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Vinil7 [7]

Answer:

square has four sides. and all four sides are equal.

so if side = x units

perimeter = x + x + x + x = 4x

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3 years ago

If 3m = 19 - n and 2m + 5n = 30, then what is the value of m?

nexus9112 [7]

Answer:

m=5

Step-by-step explanation:

We can solve this by using a system of equations. The easiest way to solve this is by using substitution.

3m=19-n Subtract both sides by 19 to find n.

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3m-19=-n Divide everything by -1 to make n positive.

/-1 /-1

n=-3m+19

Now, we can substitute n into the second equation.

2m+5(-3m+19)=30 Substitute (-3m+19) into n.

2m-15m+95=30 Simplify.

-13m+95=30 Simplify and subtract both sides by 95.

-95 -95

-13m=-65 Divide both sides by -13.

/-13 /-13

m=5

We don't need to solve for n at all, so that is the answer!

Hope this helps, and have an amazing day ♥

8 0

3 years ago

8n + 10 = 90 -2n 12 - 9i = 24 - 3i 6a + 81 = -5a - 18

Masteriza [31]

The answer for 8n + 10 = 90 - 2n is n= 8

The answer for 12 - 9i = 24 - 3i is i = -2

The answer for 6a + 81 = 5a - 18 is a= -9

3 0

4 years ago

Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is

malfutka [58]

Answer:

$m=135000000 Kg$

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

$\rho=\frac{m}{V}$

where $\rho$ is the density, $m$ is the mass and, $V$ is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

$V= (length)(heigh)(width)$ .

So for our pool

$V= (20)(50)(10)$ .

$V= 10000m^{3}$ .

Our density is in $g/mL$ , so the last thing we need to do before computing the mass is to express the density in $Kg/m^{3}$ (this is because we want our mass in $Kg$ and, we have our volume in $m^{3}$ ).