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3 years ago

Please help what is 15 2/3

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

8 0

Answer:

47/3

Step-by-step explanation:

Decimal form = 15.667

Find this by multiplying 3 by 15, then adding it by 2. That is now your numerator.

zhenek [66]3 years ago

6 0

Answer:

its

47/3 i can show u more steps how did i do it

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Musya8 [376]

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3 years ago

1. Beyunka and Latoya competed in a bowling tournament. Their scores are displayed below. If Latoya won, what statistical measur

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3 years ago

5. For the data in the table below, find the sum of the absolute deviations for the predicted values

Kipish [7]

Based on the absolute deviations and the predicted values, the sum of absolute deviations will be 4.8.

<h3>What would be the sum of absolute deviations from predicted values?</h3>

This can be found as:

= ∑ (Observed value - Predicted value)

The observed values are given in the table and the predicted values will be calculated using y = 3.6x - 0.4.

Solving gives:

= [3 - (3.6 x 1 - 0.4)] + [7 - (3.6 x 2 - 0.4)] + [ 9 - (3.6 x 3 - 0.4)] + [14 - (3.6 x 4 - 0.4)] + [15 - (3.6 x 5 - 0.4)] + [21 - (3.6 x 6 - 0.4)] + [25 - (3.6 x 7 - 0.4)]

= 0.2 + 0.2 + 1.4 + 0 + 2.6 + 0.2 + 0.2

= 4.8

Find out more on absolute deviation at brainly.com/question/447169.

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2 years ago

Find the sum of these polynomials. (4x2 + 3x - 1) + (x2 - 5x - 6) =

zhuklara [117]

Answer: 5x2-2x-7

Step-by-step explanation:

(4x2 + 3x - 1) + (x2 - 5x - 6)

=4x2+3x-1+x2-5x-6

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3 years ago

A researcher wishes to determine whether people with high blood pressure can lower their blood pressure by performing yoga exerc

Anastaziya [24]

Answer:

90% confidence interval for the difference between the two population means

( -23.4166 , -6.5834)

Step-by-step explanation:

Step(i):-

Given first sample size n₁ = 100

Given mean of the first sample x₁⁻ = 178

Standard deviation of the sample S₁ = 35

Given second sample size n₂= 100

Given mean of the second sample x₂⁻ = 193

Standard deviation of the sample S₂ = 37

Step(ii):-

Standard error of two population means

$se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{s^{2} _{1} }{n_{1} }+\frac{s^{2} _{2} }{n_{2} } }$

$se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{(35)^{2} }{100 }+\frac{(37)^{2} }{100 } }$

$se(x^{-} _{1} -x^{-} _{2} ) = 5.093$

Degrees of freedom

ν = n₁ +n₂ -2 = 100 +100 -2 = 198

t₀.₁₀ = 1.6526

Step(iii):-

90% confidence interval for the difference between the two population means

$(x^{-} _{1} - x^{-} _{2} - t_{\frac{\alpha }{2} } Se (x^{-} _{1} - x^{-} _{2}) , x^{-} _{1} - x^{-} _{2} + t_{\frac{\alpha }{2} } Se (x^{-} _{1} - x^{-} _{2})$

(178-193 - 1.6526 (5.093) , 178-193 + 1.6526 (5.093)

(-15-8.4166 , -15 + 8.4166)

( -23.4166 , -6.5834)

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3 years ago