<span>(0.058 mol I2)(253.808 g/mol I2) = 14.721 g of I2 </span>
<span>So that's the mass of I2: 14.721 g </span>
<span>Percentage is the mass of solute/(mass of solute + mass of solvent) </span>
<span>14.721/(14.721g + 105 g) </span>
<span>14.721/119.721 </span>
<span>=0.123 or 12.3%
</span>
Answer:
Fe3O4 + 2C ---> 3Fe + 2CO2.
Explanation:
Iron 3 oxide is Fe3O4 , and the equation for the reaction is
Fe3O4 + 2C ---> 3Fe + 2CO2.
Explanation:
The acid involved is ethanoic acid which is
![CH_3COOH](https://tex.z-dn.net/?f=CH_3COOH)
And the alkaline involved is calcium hydroxide which is
![Ca(OH)_2](https://tex.z-dn.net/?f=Ca%28OH%29_2)
The equation for the reaction is
![Ca(OH)_2 + CH_3COOH → (CH_3COO)_2Ca + H_2O](https://tex.z-dn.net/?f=Ca%28OH%29_2%20%2B%20CH_3COOH%20%E2%86%92%20%28CH_3COO%29_2Ca%20%2B%20%20H_2O)
Hope this helps you