CALCULATE THE MOLES IN 2.17 X10^23 MOLECULES OF FLUORINE
1 answer:
Answer:
<h2>0.36 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>0.36 moles</h3>Hope this helps you
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The original concentration of the acid solution is 6.175 10^-4 mol / L.
<u>Explanation:</u>
Concentration is the ratio of solute in a solution to either solvent or total solution. It is expressed in terms of mass per unit volume
HBr + NaOH -----> NaBr + H2O
There is a 1:1 equivalence with acid and base.
Moles of NaOH = 72.90 10^-3
0.25
= 0.0182 mol.
[ HBr ] = moles of base / volume of a solution
= 0.0182 / 29.47
= 6.175 10^-4 mol / L.
Answer:
for the reaction is 18.05
Explanation:
Equilibrium constant in terms of partial pressure () for this reaction can be written as-
where and
are equilibrium partial pressure of
and
respectively
Hence = 18.05
So, for the reaction is 18.05