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Nookie1986 [14]
3 years ago
5

CALCULATE THE MOLES IN 2.17 X10^23 MOLECULES OF FLUORINE

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

<h2>0.36 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{2.17 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{2.17}{6.02}  \\  = 0.360465...

We have the final answer as

<h3>0.36 moles</h3>

Hope this helps you

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3 years ago
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8 0
3 years ago
Given the balanced equation, 2 H2 + O2 -&gt; 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

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8 0
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