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antoniya [11.8K]
3 years ago
12

Write the electronic configuration of oxygen on the basis of sub shell.​

Chemistry
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

[He] 2s² 2p⁴

Explanation:

If you're looking for the answer in subshell form, here it is:

1sx^{2} 2sx^{2} px^{4}  (2.6)

Quote:

"Where I walk, I walk alone. Where I fight, I fight alone."

- Akuma

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How do you find moles
Marizza181 [45]
A mole is equivalent to 6.02 x 10^23 molecules at STP. Use a conversion factor like the following.
Example: The initial value x  The value you are trying to convert to
                                               ------------------------------------------------
                                              The value you are trying to get rid of

6 0
3 years ago
Read 2 more answers
AL
Helga [31]
Metallic I’m pretty sure. :)
4 0
3 years ago
A concentrated aqueous solution of Pb(NO3)2 is slowly added to 1.0 L of a mixed aqueous solution containing 0.010 M Na2CrO4 and
Oduvanchick [21]

Answer:

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

Explanation:

Step 1: Data given

Molarity of Na2CrO4 = 0.010 M

Molarity of NaBr = 2.5 M

Ksp(PbCrO4) = 1.8 * 10^–14

Ksp(PbBr2) = 6.3 * 10^–6

Step 2: The balanced equation

PbCrO4 →Pb^2+ + CrO4^2-

PbBr2  → Pb^2+ + 2Br-

Step 3: Define Ksp

Ksp PbCrO4 = [Pb^2+]*[CrO4^2-]

1.8*10^-14 = [Pb^2+] * 0.010 M

[Pb^2+] = 1.8*10^-14 /0.010

[Pb^2+] = 1.8*10^-12 M

The minimum [Pb^2+] needed to precipitate PbCrO4 is 1.8*10^-12 M

Ksp PbBr2 = [Pb^2+][Br-]²

6.3 * 10^–6 = [Pb^2+] (2.5)²

[Pb^2+] = 1*10^-6 M

The minimum [Pb^2+] needed to precipitate PbBr2 is 1*10^-6 M

This means the amount of PbCrO4 will precipitate first, with a [Pb^2+] concentration of 1.8*10^-12 M

5 0
3 years ago
How much heat does it take to melt 2.5 kg of lead when it is at its melting point (m.p. = 327.5°C; Hf = 2.04 × 104 J/kg)?
irinina [24]
1. the amount of heat that it would take would be :
5.1 x 10^4 J

2. I think the substance would be : Iron

3. the amount of heat required would be :
1.13 x 10^4 kJ

Hope this helps
6 0
3 years ago
Read 2 more answers
Help pleased alot of points​
JulsSmile [24]

Answer:

Nitrogen non metal

Gain 3 electrons

Negative ion N3-

Barium metal

Lose electrons

Positive charge

Selinium non metal

Gain electron

Negative charge

Cesium metal

Lose electrons

Positive charge

Explanation:

4 0
3 years ago
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