This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).
Answer:
52 km
Step-by-step explanation:
Given, 5 miles is 8km.
So, 1 mile will be (8/5) km.
Now, 32.5 miles will be (8/5) x 32.5 = 52 km
Hmmmmmmmmmmmmmmmmmmmmmmmmm
Answer:
She can make 27 bags
2 pieces of candy is left over
Step-by-step explanation:
She has 245 Chocolate Twisters.
she puts 9 Chocolate Twisters in each treat bag,
1 bag hold 9 chocolates
9 chocolates = 1 bag
So 245 chocolates in how many bags
Divide 245 by 9
use long division
2 7 -----------> Quotient
------------------------------------
9 245
18 (subtract it)
-------------------------
65
63 (subtract it)
----------------------------
2 -----------> remainder
She can make 27 bags
2 pieces of candy is left over
