All categories

3 years ago

ASAP PLEASE ‼️‼️❗️‼️‼️❗️

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

5 0

Answer:

I dont know what thats asking

Step-by-step explanation:

You might be interested in

Find the value of x such that the area of a triangle whose vertices have coordinates (6, 5), (8, 2) and (x, 11) is 15 square uni

Serjik [45]

Answer:

$x =12\ or\ -8$

Step-by-step explanation:

Given

$(x_1,y_1) = (6,5)$

$(x_2,y_2) = (8,2)$

$(x_3,y_3) = (x,11)$

$Area = 15$

Required

Find x

The area is calculated as thus:

$Area = \frac{1}{2}|x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$

Substitute values

$15 = \frac{1}{2}|6*(2 - 11) + 8*(11 - 5) + x(5 - 2)|$

$15 = \frac{1}{2}|6*(-9) + 8*(6) + x(3)|$

$15 = \frac{1}{2}|-54 + 48 + 3x|$

$15 = \frac{1}{2}|-6 + 3x|$

Multiply through by 2

$2 * 15 = \frac{1}{2}|-6 + 3x| * 2$

$30 = |-6 + 3x|$

Remove absolute sign

$30 = -6 + 3x\ or\ -30 = -6 + 3x$

Add 6 to both sides

$36 = 3x\ or\ -24 = 3x$

Divide by 3

$12 = x\ or\ -8 = x$

$x =12\ or\ -8$

So, the coordinates are (-8, 11) or (12,11)

3 0

2 years ago

If f(x)= 2a|3x – 9| – ax, where a is some constant not equal to zero, find f ′(3).

sineoko [7]

Hmm, it actually doesn't exist because at x=3, that is where the absoluve value turns into 0. the graph has a point at x=3 and there is no slope of a pointy part of a function. I mean the slope is undinfed, it is DNE

8 0

3 years ago

I really need help with this. Can anyone help me please?

I am Lyosha [343]

Answer:

$f(x)=(x-3)(x^2+4x+8)$

Step-by-step explanation:

A polynomial function is given by the form:

$f(x)=a(x-p)(x-q)...$

Where a is the leading coefficient, and p and q are the roots (more can be added if necessary).

Our zeros are 3 and (-2 + 2i).

And our leading coefficient a = 1.

Furthermore, by the Complex Root Theorem, if (-2 + 2i) is a zero, then (-2 - 2i) must also be a zero.

So, by substitution, we acquire:

$f(x)=1(x-(3))(x-(-2+2i))(x-(-2-2i))$

Simplify:

$f(x)=(x-3)(x+2-2i)(x+2+2i)$

Expand the second and third factors:

$\begin{aligned} &=(x+2-2i)x+(x+2-2i)(2)+(x+2-2i)(2i)\\&= (x^2+2x-2ix)+(2x+4-4i)+(2ix+4i-4i^2)\\&=(x^2)+(2x+2x)+(-2ix+2ix)+(-4i+4i)+(4-4i^2)\\&=x^2+4x+(4+4)\\&=x^2+4x+8 \end{aligned}$

Therefore, our polynomial function of least degree and the given zeros will be:

$f(x)=(x-3)(x^2+4x+8)$

6 0

3 years ago

37. A square has an area of 75 square meters.

alina1380 [7]

Answer:

C. 8.7 meters will be closest length

3 0

3 years ago

For some reason it says square but please help! I need to know step by step what to do.

quester [9]

Answer:

8.06 inches

Step-by-step explanation:

The diagram shows a rectangle with width of 4 inches and area of 28 square inches.

Use area formula:

$A_{\text{rectangle}}=\text{Width}\times \text{Length}$

So,

$28=4\times \text{Length}\Rightarrow \text{Length}=\dfrac{28}{4}=7\ \text{inches}$

By the Pythagorean theorem,

$\text{Diagonal}^2=\text{Width}^2+\text{Length}^2\\ \\\text{Diagonal}^2=4^2+7^2\\ \\\text{Diagonal}^2=16+49\\ \\\text{Diagonal}^2=65\\ \\\text{Diagonal}=\sqrt{65}\approx 8.06\ \text{inches}$

7 0

3 years ago