<span>If there is not enough carbohydrate available in cells to allow the acetyl-CoA to enter the citric acid cycle, it will be used to make ketones. Acetyl-CoA is a molecule that is important in some biochemical reactions involving protein lipid and carbohydrate metabolism. It function to transport an acetyl group to the citric acid cycle or the Krebs cycle for it to be oxidized for the production of energy. Ketone can be produced and is regulated from the acetyl-CoA. The rate of the production of this substance would increase during starvation or in other words there is less carbohydrates that is available in the body.</span>
Heyy :))
The best answer would be:
<span>Hibernating
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Answer:
Hello.
• gels can melt during electrophoresis, the buffer can become exhausted, and different forms of genetic material may run in unpredictable forms.
• And the strengths could be that it separates based on size, it is relatively easy to do.
If the researchers replaced the bacterial proton pump with a proton pump that was activated only by atp then less ATP would be produced when the light is on because no proton gradient would be available to produce ATP.
<h3>What is
proton gradient ?</h3>
Two quinol (4H+4e) oxidations at the Qo site result in the formation of one quinol (2H+2e) at the Qi site, creating a proton gradient (in total six protons are translocated: two protons reduce quinone to quinol and four protons are released from two ubiquinol molecules).
For the ETC to continue functioning, the energy trapped in the electrochemical gradient of protons across the inner mitochondrial membrane must also be released in some manner. ATP is created using the energy in the proton electrochemical gradient.
Chemiosmotic coupling is the process by which ATP synthesis is coupled to the electrochemical gradient of H+ across the inner mitochondrial membrane.
Peter Mitchell, who in 1961 made the initial suggestion, was given the Nobel Prize for his efforts in 1978.
To learn more about proton gradient from the given link:
brainly.com/question/28046848
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The answer is C Good luck
