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3 years ago

Find the value of c. 64 32 5c+2 C

Mathematics

1 answer:

Dmitry [639]3 years ago

5 0

Answer:

c = 6

Step-by-step explanation:

(I'm going to call the unidentified inner angle Henry, 'kay?)

First, we need to find Henry.

64 + Henry = 180

(64 - 64) + Henry = (180 - 64)

Henry = 116

Now to c.

Henry + 32 + 5c + 2 = 180

(116 + 32 + 2) + 5c = 180

(150 - 150) + 5c = (180 - 150)

5c/5 = 30/5

c = 6

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Answer:

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Step-by-step explanation:

we are given

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now, we can plug values

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3 years ago

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2 years ago

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3 years ago

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2 years ago

Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma

Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with $\mu = 112$ inches and $\sigma = 14$ inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - $\mu = 112$ inches

Standard deviation - $\sigma = 14$ inches

The z-score formula is given by, $Z=\frac{x-\mu}{\sigma}$

Now,

$P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})$

$P(X>140)=P(Z>\frac{140-112}{14})$

$P(X>140)=P(Z>\frac{28}{14})$

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The Z-score value we get is from the Z-table,

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Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

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3 years ago

Find the value of c. 64 32 5c+2 C​

Find the value of c. 64 32 5c+2 C