Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.
To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.
A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:
Similarly, but exchanging the role of x and y, we compute the length of BC:
So, the area of the rectangle is 
The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:
So, the area of the portion located in the third quadrant is 
This means that the ratio between the two area is
If we want this ratio to be a percentage, just make sure that the denominator is 100:
Answer:
Number 3 is correct.
129.19m
Step-by-step explanation:
You might be wondering how did I got 32⁰, well, that's because they are alternate angles.
Now, we're trying to find the opposite side of the triangle.
Using the laws,
we got cos32⁰=x/243.8
243.8cos32⁰=x
129.19⁰
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A = 9 (Sorry I can't do the other ones, I haven't learned those ones yet) Hope this helps!! :P
Answer:
Step-by-step explanation:
After removing one black marble:
Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, 
,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
