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guajiro [1.7K]
3 years ago
5

What is the least common multiple (LCM) that could be

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Answer:

the greatest common factor will be 3

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How much will the taxi driver earn if he takes one passenger 4.8 miles in another passenger 7.3 miles explain your process
Tcecarenko [31]

Answer:

12.1x+t

Step-by-step explanation:

since we do not get a specific amount we must add 4.8 and 7.3 and substitute the amount the driver earns per mile with x and use t as a variable if they charge something like $5 just to get in before driving

6 0
2 years ago
Find the common difference for the sequence shown: [1/5, 13/40, 9/20...)
bazaltina [42]
<h3>Answer:  1/8</h3>

Explanation:

Pick any term and subtract off the previous term to get the common difference.

So,

13/40 - 1/5 = 13/40 - 8/40 = (13-8)/40 = 5/40 = 1/8

Or

9/20 - 13/40 = 18/40 - 13/40 = (18-13)/40 = 5/40 = 1/8

The positive common difference value indicates this arithmetic sequence is increasing.

6 0
3 years ago
Convert 1012 into bainary number system​
rewona [7]
1111110100

Do modulo 2 then floor divide by 2 and repeat


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8 0
2 years ago
Please help! It would be very much appreciated :)
Trava [24]

Answer:

  1. Cos 45=6/x

x=6/cos 45=6√2

x=6√2

tan 45=y/6

y=tan45 ×6

y=6

2.

sin 60=y/10

y=sin60×10

y=5√3

again

Cos 60=x/10

x=½×10

x=5

3.

Sin 45=x/5

x=1/√2×5 or

x=5√2/2

again

y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]

4.

Sin 30=8/x

½×x=8

x=8*2

x=16

again

cos 30= y/x

√3/2×16=y

y=8√3

5.

sin 60=7/x

x=7/[√3/2]

x=14/√3 or 14√3/3

again

cos 60=y/x

½×14√3/3=y

7√3/2=y

y=7√3/2

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<u>C</u><u>o</u><u>s</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>b</u><u>a</u><u>s</u><u>e</u><u>/</u><u>h</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u>e</u>

<u>T</u><u>a</u><u>n</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>p</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u><u>/</u><u>b</u><u>a</u><u>s</u><u>e</u>

7 0
3 years ago
I really need this very badly, press the photo if neccessary ​
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