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3 years ago

The perimeter of a rectangular painting is 270 cm.

Mathematics

2 answers:

Ainat [17]3 years ago

7 0

The anwser is 53 cm each

kipiarov [429]3 years ago

4 0

Answer:

p/2 _l step 1. 270 ÷2= 135. 135- 82 = 53 width of the painting = 53

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Solve each system by elimination. −5x − 10y = 15 −3x + 10y = 25

yaroslaw [1]

Answer:

$\boxed{x = -5~~and~~ y =1}$

Step-by-step explanation:

-5x - 10y = 15

-3x + 10y = 25 +

-8x = 40

$x = \frac{40}{-8}$

x = -5

Substitute the value of x to one of equations

-5(-5) - 10y = 15

25 - 10y = 15

-10y = 15 - 25

-10y = -10

$y = \frac{-10}{-10}$

y = 1

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What is the best approximation for the area of this circle? Use 3.14 to approximate pi. 25.1 in² 50.2 in² 201.0 in² 803.8 in² Ci

Greeley [361]

Answer:

The best approximation is $201.0\ in^{2}$

Step-by-step explanation:

we know that

The area of the circle is equal to

$A=\pi r^{2}$

In this problem we have

$r=8\ in$

$\pi =3.14$

substitute

$A=(3.14)(8^{2})=201.0\ in^{2}$

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3 years ago

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rjkz [21]

15, Yes: a^2 +b^2 = c^2
9^2+12^2= 225
The square root of 225 is 15, therefore x=15.
Answer to question is yes.

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3 years ago

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the measure of angle s = 30 degrees, the measure of arc RS = 84 degrees and line RU is tangent to the circle at R. Find m angle

Paul [167]

Let O be the center of a circle. If the measure of arc RS is 84 degrees, then m∠SOR=84^{0}. The triangle SOR is isoscales (because SO=OR as radii), so m∠RSO=m∠ORS=(180^{0}-84^{0}):2=48^{0}.

Line RU is tangent to the circle in point R, this means that m∠ORU=90^{0}.
Consider the triangle SRU. m∠RSU=30^{0} and m∠SRU=48^{0}+90^{0}=138^{0}, then m∠RUS=180^{0}-30^{0}-138^{0}=12^{0}.
ANSWER: Correct choice B - 12^{0}.

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3 years ago

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Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Nu

Tasya [4]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Answer:

a. Cumulative Probability Distribution

Grade P(X ≤ x)

F 0.145

D 0.310

C 0.670

B 0.910

A 1

b. P(at least B) = 0.330

c. P(pass) = 0.855

Step-by-step explanation:

Professor Sanchez has been teaching Principles of Economics for over 25 years.

He uses the following scale for grading.

Grade Numerical Score Probability

A 4 0.090

B 3 0.240

C 2 0.360

D 1 0.165

F 0 0.145

a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)

The cumulative probability distribution is given by

Grade = F

P(X ≤ x) = 0.145

Grade = D

P(X ≤ x) = 0.145 + 0.165 = 0.310

Grade = C

P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670

Grade = B

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910

Grade = A

P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1

Cumulative Probability Distribution

Grade P(X ≤ x)

F 0.145

D 0.310

C 0.670

B 0.910

A 1

b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)

At least B means equal to B or greater than B grade.

P(at least B) = P(B) + P(A)

P(at least B) = 0.240 + 0.090

P(at least B) = 0.330

c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)

Passing the course means getting a grade of A, B, C or D

P(pass) = P(A) + P(B) + P(C) + P(D)

P(pass) = 0.090 + 0.240 + 0.360 + 0.165

P(pass) = 0.855

Alternatively,

P(pass) = 1 - P(F)

P(pass) = 1 - 0.145

P(pass) = 0.855

4 0

3 years ago