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malfutka [58]
2 years ago
14

y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.

Mathematics
1 answer:
Elan Coil [88]2 years ago
3 0

General vertex form:

y = m(x − a)² + b  \: with  \: vertex \:  at \:  (a, b)

Given :

y = 2x² + 5x  - 3

Extract "spread factor" m

y = 2( x² +  \frac{5}{2} x) - 3

Complete the square

y = 2(x²  +  \frac{5}{2}x + ( \frac{5}{4})²) - 3

- 2( \frac{5}{4})²

Write as a squared binomial and simplify the constant

y = 2(x +  \frac{5}{4})² - 6 \frac{1}{8}

Re-write to match signs of standard general form:

y = 2(x - ( -  \frac{5}{4}))² \:  + ( - 6 \frac{1}{8})

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Write in slope intercept form the equation of a line that has the slope of 1/3 and the y- intercept of 5.
ludmilkaskok [199]

Answer:

y = 1/3x + 5

Step-by-step explanation:

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b is the y intercept

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y = 1/3x + 5

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3 years ago
The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th
makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 e^{kt}

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070  e^{3k}

\frac{9000}{4070} = e^{3k}

\frac{900}{407}=e^{3k}

<u><em>Taking natural logarithm on both sides, we get:</em></u>

ln\frac{900}{407}=ln(e^{3k})

ln\frac{900}{407}= 3k ln<em>e</em>

ln<em>e</em>=1

ln \frac{900}{407}= 3k

or k = \frac{1}{3}ln\frac{900}{(407)}

k =\frac{1}{3}(0.7936)

<em>k = 0.2645</em>

<em />

7 0
3 years ago
What is the midpoint of the line segment with endpoints ( 3.5,2.2) and (1.5,-4.8)?
Fantom [35]

Answer:

Option A) (2.5,-1.3) is correct

The midpoint of the given line segment is M=(2.5,-1.3)

Step-by-step explanation:

Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)

To find the mid point of these endpoints midpoint formula is M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

Let (x_1,y_1) be the point (3.5, 2.2) and (x_2, y_2) be the point (1.5, -4.8)

substituting the points in the formula

M=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)

M=\left(\frac{3.5+1.5}{2}, \frac{2.2-4.8}{2}\right)

=\left(\frac{5}{2}, \frac{-2.6}{2}\right)

=\left(2.5,-1.3\right)

Therefore M=(2.5,-1.3)

The midpoint of the given line segment is M=(2.5,-1.3)

8 0
3 years ago
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