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Lelu [443]
2 years ago
9

Help I've got 5min to figure it out 20 points for 1st actual answer and brainlyist​

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
4 0
Chronological order
Hoped this help
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Write in slope-intercept form and show work:<br> 6x + 4y = 700
Basile [38]
6x + 4y = 800
-6x -6x
--------------------
4y = -6x + 800
÷4 ÷4 ÷4
---------------------
y = -6/4x + 200

First subtract, then divide, and then you have it. 6/4 is your slope. Your rise is -6 and your run is 4.
4 0
3 years ago
Use the given equation to complete the table:
Ne4ueva [31]

Answer:

hope this helps

5 0
3 years ago
Please help I’ll give you brainlist or something
harkovskaia [24]

Answer:

1 slope of f is 5

slop of g is 2

2. connor

initial value is 200

rate of change is -10

Pilar

initial value is 242

rate of change is -8

3.

y intercept of f is -3

y intercept of g is -1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the distance between the points (7,–9) and (–2,–4).
Alexandra [31]
The answer would be √106
4 0
3 years ago
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If h(x)=\frac{f(x)}{g(x)}, then:

h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}

Since in our case we want the derivative of h(x) at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}

which, by replacing with the given numerical values:

f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3

becomes:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0

3 0
3 years ago
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