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2 years ago

PLEASE PLEASEEEEEEE HELPPPPPPPP

Mathematics

2 answers:

Rufina [12.5K]2 years ago

7 0

Answer:

Set 2 x 2 − 6 x − 8 equal to 0 . 2 x 2 − 6 x − 8 = 0

Step-by-step explanation:

Those are the zeros

Please give me brainliest

soldier1979 [14.2K]2 years ago

7 0

So you definately wrote something wrong but I will assume the 6x^2 was meant to be just 6x.

2x^2 + 6x + 2 = 0

x^2 + 3x + 1 = 0

I can't seem to find a better way than to simply use the quadratic formula:

(-3 + sqrt(9 - 4*1*1))/2 $\approx$ -0.382

(-3 - sqrt(9 - 4*1*1))/2 $\approx$ -2.62

So the zeroes for this function are at

(-0.382, 0) and (-2.62, 0)

Or exactly:

((-3 + sqrt(9 - 4*1*1))/2, 0) and ((-3 - sqrt(9 - 4*1*1))/2, 0)

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Answer:

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The graph is attached.

Step-by-step explanation:

You need to remember the meaning of the inequalities symbols:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$