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2 years ago

Write an equation for the line parallel to the given line that contains C.

Mathematics

1 answer:

lyudmila [28]2 years ago

6 0

ANSWER

$y= - 4x + 18$

EXPLANATION

The given line has equation;

$y = - 4x + 5$

The slope of this line is

-4

The given line is parallel to this line so it has the same slope:

$m = - 4$

The equation of this line is in the form:

$y-y_1=m(x-x_1)$

We substitute the slope and the point:

(3,6)

$y-6= - 4(x-3)$

$y= - 4x + 12+ 6$

$y= - 4x + 18$

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What is the 6th term of the geometric sequence 1024,528,256

zmey [24]

167 i believe according to my calculations

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3 years ago

Tickets to a school play are $4.50 for an adult and $3.00 for a student. If 300 tickets are sold and $1087.50 collected, how man

Kryger [21]

Answer:

<h2>125 tickets for an adult</h2><h2>and 175 tickets for a student</h2>

Step-by-step explanation:

$a-\text{number of the tickets for an adult}\\s-\text{number of the tickets for a student}\\\\(1)\qquad a+s=300\\(2)\qquad4.5a+3s=1087.5\\------------\\(1)\\a+s=300\qquad\text{subtstitute}\ s\ \text{from both sides}\\a=300-s\\\\\text{Put it to (2):}\\\\4.5(300-s)+3s=1087.5\qquad\text{use distributive property}\\\\(4.5)(300)+(4.5)(-s)+3s=1087.5\\\\1350-4.5s+3s=1087.5\qquad\text{subtract 1350 from both sides}\\\\-1.5s=-262.5\qquad\text{divide both sides by (-1.5)}\\\\\boxed{s=175}$

$\text{Put the value of}\ s\ \text{to (1):}\\\\a=300-175\\\\\boxed{a=125}$

3 0

2 years ago

Recipe ingredients remain in a constant ratio no matter how many servings are prepared. Which table shows a possible ratio table

Phantasy [73]

A table which shows a possible ratio table for ingredients X and Y for the given number of servings is table 4.

<h3>What is a proportion?</h3>

A proportion can be defined as an equation which is typically used to represent (indicate) the equality of two (2) ratios. This ultimately implies that, proportions can be used to establish that two (2) ratios are equivalent and solve for all unknown quantities.

Mathematically, a direct proportion can be represented the following equation:

y = kx

<u>Where:</u>

y and x are the variables.
k represents the constant of proportionality.

Since the recipe ingredients remain in a constant ratio, we have:

k = y/x

For table 1, we have:

k = 2/1 = 2.

k = 3/2 = 1.5.

k = 4/3.

For table 2, we have:

k = 2/1 = 2.

k = 4/2 = 2.

k = 8/3.

For table 3, we have:

k = 2/1 = 2.

k = 3/2 = 1.5.

k = 5/3.

For table 4, we have:

k = 2/1 = 2.

k = 4/2 = 2.

k = 6/3 = 2.

In conclusion, a table which shows a possible ratio table for ingredients X and Y for the given number of servings is table 4 as shown in the image attached below.

Read more on proportionality here: brainly.com/question/12866878

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10 months ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

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3 years ago

Write first three common multiple of 3 , 5 and 6

ratelena [41]

Answer:

LCM of 3, 5, and 6 is the smallest number among all common multiples of 3, 5, and 6. The first few multiples of 3, 5, and 6 are (3, 6, 9, 12, 15 . . .), (5, 10, 15, 20, 25 . . .), and (6, 12, 18, 24, 30 . . .) respectively. There are 3 commonly used methods to find LCM of 3, 5, 6 - by division method, by prime factorization, and by listing multiples.

Step-by-step explanation:

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2 years ago

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