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stellarik [79]
3 years ago
5

Test question plz help

Mathematics
1 answer:
Levart [38]3 years ago
3 0

Answer:

Step-by-step explanation:

(3,6)

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While playing blackjack, a gambler loses $17.00 on his first hand, then wins $14.00, and then loses $21.00. Find the gambler’s n
zubka84 [21]

Answer:

Step-by-step explanation:18

8 0
4 years ago
Read 2 more answers
A real estate agent has surveyed houses in twenty nearby zip codes in an attempt to put together a comparison for a new property
gladu [14]

Answer:

A a house in that market that sells for ​$300,000 is unusual.

Step-by-step explanation:

Let the random variable <em>X</em> denote the price of a house and the random variable <em>Y</em> denote the living area of a house.

The number of houses surveyed by the real estate agent is, <em>n</em> = 1057.

Assume that both the random  variables, <em>X </em>and <em>Y</em> are approximately normally distributed.

That is,

X\sim N(\$169400,\ \$68438)\\\\Y\sim N(2058\ \text{sq. ft.},\ 790\ \text{sq. ft.})

To compute the probability of a Normal distribution we first need to convert the raw scores to <em>z</em>-scores.

z=\frac{\text{Raw score}-\mu}{\sigma}

A <em>z</em>-score higher than 1.96 and lower than -1.96 are considered unusual. The values having these <em>z</em>-scores are considered as outliers.

(1)

Compute the <em>z</em>-score for <em>X</em> = 300000 as follows:

z=\frac{X-\mu}{\sigma}\\\\=\frac{300000-169400}{68438}\\\\=2.70

(2)

Compute the <em>z</em>-score for <em>Y</em> = 3000 as follows:

z=\frac{Y-\mu}{\sigma}\\\\=\frac{3000-2058}{790}\\\\=1.19

The <em>z</em>-score for a house in that market that sells for ​$300,000 is more than 1.96.

This implies, that the price $300,000 is unusually high.

The complete statement is:

The house that sells for ​$300 comma 000 has a​ z-score of <u>2.70</u> and the house with 3000 sq ft has a​ z-score of <u>1.19</u>.

5 0
3 years ago
If p(x) = x2 – 1 and q(x) = 5(x-1) which expression is equivalent to (p – q)(x)?
lilavasa [31]

Answer:

Option C is correct.

The expression which is equivalent to (p-q)(x)  is, x^2 -1 - 5(x-1)

Step-by-step explanation:

Given: p(x) = x^2 -1 and q(x) = 5(x-1)

To find the expression which is equivalent to (p-q)(x):

here p and q both are function assuming;

we can write the expression :

(p-q)(x) = p(x) - q(x) = x^2 -1 - 5(x-1)

therefore, the expression which is equivalent to (p-q)(x)  is;   x^2 -1 - 5(x-1)

3 0
4 years ago
Read 2 more answers
Danny decided to invest his $500 tax refund rather than spending it. He found a bank that would pay him 4% interest, compounded
Blababa [14]
Present value, PV = $500
Future value, FV = 2*PV = 2*500 = $1,000
Rate, r = 4% = 0.04
Compounding times in a year, n = 4 (compounded quarterly)
Time, t = ??

The future value expression is stated as:
FV = PV (1+r/n)^nt

Substituting;
1000 = 500 (1+0.04/4)^4t
2 = (1.01)^4t
ln 2 = 4t ln 1.01
0.6931 = 4t* 0.00995
0.6931 = 0.0398t
t = 17.414 years

Time required for the amount to double is 17.41 years.
5 0
4 years ago
87th term of 12,0,-12
Elan Coil [88]

Answer:

a_{87} = -1020

Step-by-step explanation:

Given:

The given AP is.

12,0,-12,......

n=87

The first term of an AP a=12

Common difference d=0-12=-12

We use the the formula for nth term of an AP.

a_{n} = a+(n-1)d

for 87th term

a_{87} = 12+(87-1)(-12)

a_{87} = 12+(86)(-12)

a_{87} = 12+(-1032)

a_{87} = 12-1032

a_{87} = -1020

Therefore, The 87th term of given series is -1020.

5 0
3 years ago
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