You can think about the word ‘of’ when you multiply.

2 answers:

7 0

<h3><u><em>question says</em></u></h3><h3><u><em></em></u></h3><h3><u><em>you can think about the word of you multiply</em></u></h3><h3><u><em></em></u></h3><h3><u><em>use the drop-down menus to complete the equations and statement below. </em></u></h3><h3><u><em></em></u></h3><h3><u><em>2/3 of 6 =?</em></u></h3><h3><u><em></em></u></h3><h3><u><em>2/3 x 6 =?</em></u></h3><h3><u><em></em></u></h3><h3><u><em>6 multiplied by 2/3 ????? 6.</em></u></h3><h3><u><em></em></u></h3><h3><u><em></em></u></h3><h3><u><em>answers is </em></u></h3><h3><u><em></em></u></h3><h3><u><em>2/3 of 6 = 4</em></u></h3><h3><u><em></em></u></h3><h3><u><em>2/3 x 6 = 4 </em></u></h3><h3><u><em></em></u></h3><h3><u><em>6 multiplied by 2/3 is greater than if not less than but equal to is wrong!!! i got it wrong my self sorry but everything else is right</em></u></h3>

Vlada [557]2 years ago

4 0

Answer:

$23 \: of \: 6 \\ 23 \times 6 \\ = > \frac{ \binom{23}{ \times 6} }{138} \\ 23 \: of \: 6 = 138$

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1. Trevor saves 2/3 of the money he earns at his

AveGali [126]

Trevor will be saving less amount

<u>Step-by-step explanation:</u>

To know whether he will save less, more or the same amount, we need to find $\frac{1}{4} \times \frac{2}{3}$ and then compare with $\frac{2}{3}$

Now, combine the fractions using the rule:

$\frac{a}{b} \times \frac{c}{d}=\frac{a \times c}{b \times d}$

$\frac{1}{4} \times \frac{2}{3}=\frac{1 \times 2}{4 \times 3}=\frac{2}{12}=\frac{1}{6}$

$\frac{1}{4} \times \frac{2}{3}$ is less than the fraction $\frac{1}{4}$ . Hence, concluding that Trevor will be saving less than $\frac{2}{3}$ amount.

4 0

2 years ago

Help

alisha [4.7K]

Answer:

Bro same question for my test

Step-by-step explanation:

6 0

3 years ago

Given f(x)=2^x and g(x)=f(x-3)+4, write the new function rule (equation) for function g and describe (using words*) the two tran

miss Akunina [59]

Answer:

The first thing we do is find out what f(x-3) is
$f(x)=2^x\\f(x-3)=2^{x-3}$ this is can be simplified using the rules of exponents
$f(x-3)=2^{x-3}\\f(x-3)=2^x\div2^3\\f(x-3)=\frac{2^{x}}{8}$
Then we put that into g(x)
$g(x)=f(x-3)+4\\g(x)=\frac{2^{x}}{8}+4$
The first transformation is at f(x), where it is divided by 8, and then inserted into g(x) which increases the new transformed f(x) by 4