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3 years ago

PLZZZ HELP ITS DUE AT 1:45

Mathematics

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

a= 10 b= -13 c= -3

Step-by-step explanation:

First, you multiply 5x+1 and 2x-3

You then end up with 10x^2-13x-3 which is in ax^2+bx+c form

So, a would be 10, b would be -13, and c would be -3.

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(England,

murzikaleks [220]

Answer:

∠JKL = 38°

Step-by-step explanation:

PQRS, JQK and LRK are straight lines

Let's take the straight lines in the diagrams one after the other to find what they consist.

The related diagram can be found at brainly (question ID: 18713345)

Find attached the diagram used for solving the question.

For straight line PQRS,

2x°+y°+x°+2y° = 180°

(Sum of angles on a Straight line = 180°)

Collect like terms

3x° + 3y° = 180°

Also straight line PQRS = straight line PQR + straight line SRQ

For straight line PQR,

2y + x + ∠RQM = 180° ....equation 1

For straight line SRQ,

2x + y + ∠MRQ = 180° ....equation 2

Straight line PQRS = addition of equation 1 and 2

By collecting like times

3x +3y + ∠RQM + ∠MRQ = 360°....equation 3

Given ∠QMR = 33°

∠RQM + ∠MRQ + ∠QMR = 180° (sum of angles in a triangle)

∠RQM + ∠MRQ + 33° = 180°

∠RQM + ∠MRQ = 180-33

∠RQM + ∠MRQ = 147° ...equation 4

Insert equation 4 in 3

3x° +3y° + 147° = 360°

3x +3y = 360 - 147

3x +3y = 213

3(x+y) = 3(71)

x+y = 71°

∠JQP = ∠RQK = 2y° (vertical angles are equal)

∠LRS = ∠QRK = 2x° (vertical angles are equal)

∠QRK + ∠RQK + ∠QKR = 180° (sum of angles in a triangle)

2x+2y + ∠QKR = 180

2(x+y) + ∠QKR = 180

2(71) + ∠QKR = 180

142 + ∠QKR = 180

∠QKR = 180 - 142

∠QKR = 38°

∠JKL = ∠QKR = 38°

5 0

3 years ago

What is 1 ten more than 9 ones

Evgesh-ka [11]

19 because 1 ten = 10 ones and 9 one plus 10 ones equals 19 altogether

6 0

3 years ago

What is the solution of -8/2y-8=5/y+4-7y+8/y^2-16

Mnenie [13.5K]

<h2>Answer:</h2>

The solution of the given equation is:

y=6

<h2>Step-by-step explanation:</h2>

The expression is given by:

$\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}$

Now on solving for the given equation

$\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}-\dfrac{7y+8}{(y-4)(y+4)}$

since,

$a^2-b^2=(a-b)(a+b)\\\\so,\\\\y^2-16=y^2-4^2\\\\i.e.\\\\y^2-16=(y-4)(y+4)$

Hence, we get:

$\dfrac{-4}{y-4}=\dfrac{5\times (y-4)-(7y+8)}{(y+4)(y-4)}\\\\i.e.\\\\\dfrac{-4}{y-4}=\dfrac{5y-20-7y-8}{(y-4)(y+4)}$

$-4\times (y-4)(y+4)=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4\times (y+4))=(-2y-28)(y-4)\\\\i.e.\\\\(y-4)(-4y+16)=(-2y-28)(y-4)\\\\i.e.$

$(y-4)(-4y+16)-(-2y-28)(y-4)=0\\\\i.e.\\\\(y-4)(-4y-16+2y+28)=0\\\\i.e.\\\\(y-4)(-2y+12)=0\\\\i.e.$

$y-4=0\ or\ -2y+12=0\\\\i.e.\\\\y=4\ or\ 2y=12\\\\i.e.\\\\y=4\ or\ y=6$

but y≠ 4

since, the denominator of the term in the left side of the given equality and the second term in the right side of the given equality will be zero and hence, the expression will be not defined.

Hence, the value of y is: 6

7 0

3 years ago

Read 2 more answers

Will give BRAINLIEST!!!!!! Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. f(x) = x2 - 3 and g(x)

igomit [66]

Answer:

Answer:

f(g(x)) = g(f(x)) = x and f and g are the inverses of each other.

Step-by-step explanation:

Here, the given functions are:

To Show: f (g(x)) = g (f (x))

(1) f (g(x))

Here, by the composite function:

⇒ f (g(x)) = x

(2) g (f(x))

Here, by the composite function:

⇒ g (f(x)) = x

Hence, f(g(x)) = g(f(x)) = x

⇒ f and g are the inverses of each other.

4 0

3 years ago

Solve the inequality: -4x -7>1

anastassius [24]

Answer:

1. x < -2

2. Yes

Step-by-step explanation:

-4x - 7 > 1

= -4x > 8

= x < -2

5 0

3 years ago