Answer:-
0.648 M
Explanation:-
Volume of Ba(OH)2= 34.63ml/1000=0.03463 litre
Number of moles of Ba(OH)2 = 0.3275 M x 0.03463 litre
= 0.01134 moles
Since Ba(OH)2 has 2 OH in its formula,
Number of moles of OH- = 2 x 0.01134=0.02268 moles.
Volume of HCl= 35ml/1000 = 0.035 litre
At the end point number of moles of H+ = number of moles of OH-.
Number of moles of HCL= Concentration of HCl x Volume of HCl
∴ Concentration of HCl = 0.02268 moles/ 0.035 litre
= 0.648 moles/ litre
= 0.648 M
Answer:
Lead to Sulfur = 2 : 1
Explanation:
Given
Represent lead with L and Sulfur with S
L1 = 6.46g for S1 = 1 g
L2= 3.23g for S2 = 1 g
Required
Determine the simple whole number ratio of L to S
Divide L1 by L2
L = L1/L2
L = 6.46g/3.23g
L = 2
Divide S1 by S2
S = 1g/1g
S = 1
Represent L and S as a ratio:
L : S = 2 : 1
Hence, the required ratio of Lead to Sulfur is 2 to 1
Q=mcT
125cal=(60.0g)(0.0920)(T-21)
[(125)/(60)(0.0920)]+21=T2
T2=43.6C
<u>Answer:</u> The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate
<u>Explanation:</u>
We are given:
Average number of drops of sodium bicarbonate = 142
The chemical equation for the reaction of sodium bicarbonate and acetic acid in vinegar follows:
From the stoichiometry of the reaction:
1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.
Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate
