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3 years ago

In one compound of lead and sulfur, there are 6.46 g of lead

Chemistry

1 answer:

timurjin [86]3 years ago

4 0

Answer:

Lead to Sulfur = 2 : 1

Explanation:

Given

Represent lead with L and Sulfur with S

L1 = 6.46g for S1 = 1 g

L2= 3.23g for S2 = 1 g

Required

Determine the simple whole number ratio of L to S

Divide L1 by L2

L = L1/L2

L = 6.46g/3.23g

L = 2

Divide S1 by S2

S = 1g/1g

S = 1

Represent L and S as a ratio:

L : S = 2 : 1

Hence, the required ratio of Lead to Sulfur is 2 to 1

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Given:

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