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Diano4ka-milaya [45]
3 years ago
9

How many molecules of glucose is needed to undergo cell respiration?

Biology
1 answer:
masya89 [10]3 years ago
6 0

Answer:

<em><u>One molecule of glucose is needed to produce approximately 38 molecules of ATP in each round of aerobic respiration.</u></em>

Explanation:

In respiration, organisms use food, or glucose made in photosynthesis to obtain energy. Photosynthesizing organisms use light to synthesize chemical energy.

Mitochondria in some organisms provide the most favorable environment for energy metabolism, glucose undergoes a form of combustion, this results in carbon dioxide and water production, together with energy as ATP or adenosine triphosphate.  

<h3> </h3><h3>C6H12O6 (glucose) + 6 O2 → 6 CO2 + 6 H2O + ≅38 ATP </h3>

<em>    glucose+ oxygen                      →  carbon dioxide+ water+ energy </em>

Thus, only one molecule of glucose is needed to produce approximately 38 molecules of ATP.

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1.you produce d)more CO2 since the rate of this reaction increases(C6H12O6+O2--->CO2+H2O)

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which statement about the rate of prenatal development is true? 1. All the cells of all organisms divide at the same rate 2. The
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A man borrowed money at a bank $1400 at the rate o 3% for 3 years. a) Find the simple interest b) Find th total money repaid aft
zhannawk [14.2K]

Answer:

a) The simple interest is $126.

b) The total money repaid after 3 years is $1526.

Step-by-step explanation:

A man borrowed money at a bank $1400 at the rate o 3% for 3 years.

a) Find the simple interest

\longrightarrow{\sf{\red{S.I =  \dfrac{PRT}{100}}}}

  • → S.I = Simple Interest
  • → P = Principal
  • → R = Rate
  • → T = Time

Substituting all the given values in the formula to find the Simple Interest :

\longrightarrow{\sf{S.I =  \dfrac{PRT}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{P \times R \times T}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{1400 \times 3 \times 3}{100}}}

\longrightarrow{\sf{S.I =  \dfrac{14 \cancel{00}\times 3 \times 3}{1 \cancel{00}}}}

\longrightarrow{\sf{S.I = 14 \times 3 \times 3}}

\longrightarrow{\sf{S.I = 42 \times 3}}

\longrightarrow{\sf{S.I = 126}}

\star{\underline{\boxed{\pmb{\sf{S.I = \$126}}}}}

Hence, the simple interest is $126.

━━━━━━━━━━━━━━━━

b) Find the total money repaid after 3 years

\dashrightarrow{\sf{\pink{A = P + S.I }}}

  • → A = Amount
  • → P = Principal
  • → S.I = Simple Interest

Substituting all the given values in the formula to find the Amount :

\dashrightarrow{\sf{A = P + S.I }}

\dashrightarrow{\sf{A = 1400 + 126 }}

\dashrightarrow{\sf{A = 1526}}

\star{\underline{\boxed{\pmb{\sf{A = \$1526}}}}}

Hence, the total money repaid after 3 years is $1526.

\rule{300}{2.5}

3 0
2 years ago
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